Checking for an empty result (PHP, PDO, and MySQL)
Solution 1:
You're throwing away a result row when you do $sth->fetchColumn()
. That's not how you check if there are any results. You do
if ($sth->rowCount() > 0) {
... got results ...
} else {
echo 'nothing';
}
Relevant documentation is here: PDOStatement::rowCount
Solution 2:
If you have the option of using fetchAll() then, if there are no rows returned, it will just be an empty array.
count($sql->fetchAll(PDO::FETCH_ASSOC))
will return the number of rows returned.
Solution 3:
You should not use rowCount for SELECT statements as it is not portable. I use the isset function to test if a select statement worked:
$today = date('Y-m-d', strtotime('now'));
$sth = $db->prepare("SELECT id_email FROM db WHERE hardcopy = '1' AND hardcopy_date <= :today AND hardcopy_sent = '0' ORDER BY id_email ASC");
// I would usually put this all in a try/catch block, but I kept it the same for continuity
if(!$sth->execute(array(':today'=>$today)))
{
$db = null;
exit();
}
$result = $sth->fetch(PDO::FETCH_OBJ)
if(!isset($result->id_email))
{
echo "empty";
}
else
{
echo "not empty, value is $result->id_email";
}
$db = null;
Of course this is only for a single result, as you might have when looping over a dataset.
I thought I would weigh in as I had to deal with this lately.
Solution 4:
$sql = $dbh->prepare("SELECT * from member WHERE member_email = '$username' AND member_password = '$password'");
$sql->execute();
$fetch = $sql->fetch(PDO::FETCH_ASSOC);
// if not empty result
if (is_array($fetch)) {
$_SESSION["userMember"] = $fetch["username"];
$_SESSION["password"] = $fetch["password"];
echo 'yes this member is registered';
}else {
echo 'empty result!';
}