PermissionError: [Errno 13] in Python
Just starting to learn some Python and I'm having an issue as stated below:
a_file = open('E:\Python Win7-64-AMD 3.3\Test', encoding='utf-8')
Traceback (most recent call last):
File "<pyshell#9>", line 1, in <module>
a_file = open('E:\Python Win7-64-AMD 3.3\Test', encoding='utf-8')
PermissionError: [Errno 13] Permission denied: 'E:\\Python Win7-64-AMD 3.3\\Test\
Seems to be a file permission error, if any one can shine some light it would be greatly appreciated.
NOTE: not sure how Python and Windows files work but I'm logged in to Windows as Admin and the folder has admin permissions.
I have tried changing .exe
properties to run as Admin.
When doing;
a_file = open('E:\Python Win7-64-AMD 3.3\Test', encoding='utf-8')
...you're trying to open a directory as a file, which may (and on most non UNIX file systems will) fail.
Your other example though;
a_file = open('E:\Python Win7-64-AMD 3.3\Test\a.txt', encoding='utf-8')
should work well if you just have the permission on a.txt
. You may want to use a raw (r
-prefixed) string though, to make sure your path does not contain any escape characters like \n
that will be translated to special characters.
a_file = open(r'E:\Python Win7-64-AMD 3.3\Test\a.txt', encoding='utf-8')
For me, I was writing to a file that is opened in Excel.
For me, I got this error when I was trying to write a file to a folder and wanted to make sure the folder existed. I accidentally used:
path = Path("path/to/my/file.txt")
path.mkdir(parents=True, exist_ok=True)
with open(path, "w") as file:
...
but the second line means "make a directory at this exact path (and make its parents too, without throwing errors for them existing already)". The third line then throws a PermissionError
, because you can't use open()
on a directory path, of course! The second line should have been:
path.parent.mkdir(parents=True, exist_ok=True)