How to remove decimal part from a number in C#

Well 12 and 12.00 have exactly the same representation as double values. Are you trying to end up with a double or something else? (For example, you could cast to int, if you were convinced the value would be in the right range, and if the truncation effect is what you want.)

You might want to look at these methods too:

• Math.Floor
• Math.Ceiling
• Math.Round (with variations for how to handle midpoints)
• Math.Truncate

If you just need the integer part of the double then use explicit cast to int.

int number = (int) a;

You may use Convert.ToInt32 Method (Double), but this will round the number to the nearest integer.

value, rounded to the nearest 32-bit signed integer. If value is halfway between two whole numbers, the even number is returned; that is, 4.5 is converted to 4, and 5.5 is converted to 6.

Use Decimal.Truncate

It removes the fractional part from the decimal.

int i = (int)Decimal.Truncate(12.66m)