Importing functions from a shell script
According to the “Shell Builtin Commands” section of the bash manpage, .
aka source
takes an optional list of arguments which are passed to the script being sourced. You could use that to introduce a do-nothing option. For example, script.sh
could be:
#!/bin/sh
foo() {
echo foo $1
}
main() {
foo 1
foo 2
}
if [ "${1}" != "--source-only" ]; then
main "${@}"
fi
and unit.sh
could be:
#!/bin/bash
. ./script.sh --source-only
foo 3
Then script.sh
will behave normally, and unit.sh
will have access to all the functions from script.sh
but will not invoke the main()
code.
Note that the extra arguments to source
are not in POSIX, so /bin/sh
might not handle it—hence the #!/bin/bash
at the start of unit.sh
.
Picked up this technique from Python, but the concept works just fine in bash or any other shell...
The idea is that we turn the main code section of our script into a function. Then at the very end of the script, we put an 'if' statement that will only call that function if we executed the script but not if we sourced it. Then we explicitly call the script() function from our 'runtests' script which has sourced the 'script' script and thus contains all its functions.
This relies on the fact that if we source the script, the bash-maintained environment variable $0
, which is the name of the script being executed, will be the name of the calling (parent) script (runtests
in this case), not the sourced script.
(I've renamed script.sh
to just script
cause the .sh
is redundant and confuses me. :-)
Below are the two scripts. Some notes...
-
$@
evaluates to all of the arguments passed to the function or script as individual strings. If instead, we used$*
, all the arguments would be concatenated together into one string. - The
RUNNING="$(basename $0)"
is required since$0
always includes at least the current directory prefix as in./script
. - The test
if [[ "$RUNNING" == "script" ]]...
. is the magic that causesscript
to call the script() function only ifscript
was run directly from the commandline.
script
#!/bin/bash
foo () { echo "foo()"; }
bar () { echo "bar()"; }
script () {
ARG1=$1
ARG2=$2
#
echo "Running '$RUNNING'..."
echo "script() - all args: $@"
echo "script() - ARG1: $ARG1"
echo "script() - ARG2: $ARG2"
#
foo
bar
}
RUNNING="$(basename $0)"
if [[ "$RUNNING" == "script" ]]
then
script "$@"
fi
runtests
#!/bin/bash
source script
# execute 'script' function in sourced file 'script'
script arg1 arg2 arg3
If you are using Bash, a similar solution to @andrewdotn's approach (but without needing an extra flag or depending on the script name) can be accomplished by using BASH_SOURCE
array.
script.sh:
#!/bin/bash
foo () { ... }
bar () { ... }
main() {
code
}
if [[ "${#BASH_SOURCE[@]}" -eq 1 ]]; then
main "$@"
fi
run_tests.sh:
#!/bin/bash
. script.sh
# Unit tests
If you are using Bash, another solution may be:
#!/bin/bash
foo () { ... }
bar () { ... }
[[ "${FUNCNAME[0]}" == "source" ]] && return
code