PG::Error: SELECT DISTINCT, ORDER BY expressions must appear in select list
I know this is a rather old question, but I just went through a small example in my head which helped me understand why Postgres has this seemingly odd restriction on SELECT DISTINCT / ORDER BY columns.
Imagine you have the following data in your Rsvp table:
event_id | start_time
----------+------------------------
0 | Mar 17, 2013 12:00:00
1 | Jan 1, 1970 00:00:00
1 | Aug 21, 2013 16:30:00
2 | Jun 9, 2012 08:45:00
Now you want to grab a list of distinct event_ids, ordered by their respective start_times. But where should 1
go? Should it come first, because the one tuple starts on Jan 1, 1970, or should it go last because of the Aug 21, 2013?
As the database system can't make that decision for you and the syntax of the query can't depend on the actual data it might be operating on (assuming event_id
is unique), we are restricted to ordering only by columns from the SELECT
clause.
As for the actual question - an alternative to Matthew's answer is using an aggregate function like MIN
or MAX
for the sorting:
SELECT event_id
FROM Rsvp
GROUP BY event_id
ORDER BY MIN(start_time)
The explicit grouping and aggregation on start_time
permit the database to come up with a unambiguous ordering of the result tuples. Note however, that readability is definitely an issue in this case ;)
The ORDER BY clause can only be applied after the DISTINCT has been applied. Since only the fields in the SELECT statement are taken into consideration for the DISTINCT operations, those are the only fields may be used in the ORDER BY.
Logically, if you just want a distinct list of event_id values, what order they occur in should be irrelevant. If order does matter, then you should add the start_time to the SELECT list so that there is context for the order.
Also, these two SELECT clauses are NOT equivalent, so be careful:
SELECT DISTINCT(event_id, start_time) FROM ...
SELECT DISTINCT event_id, start_time FROM ...
The second is the form you want. The first will return a series of records with the data represented as a ROW construct (a single column with a tuple inside). The second will return normal columns of data output. It only works as expected in the single-column case where the ROW construct is reduced down since it is only a single column.
Because, you are using start_time column, you can use row_number() which is one of Window Functions of PostgreSQL and stack it in
-
order of start_time, if you are expecting row values with first start_time
Select event_id from (SELECT event_id ,ROW_NUMBER() OVER(PARTITION BY event_id ORDER BY start_time) AS first_row FROM Rsvp) where first_row = 1
-
reverse order of start_time, if you are expecting row values with last start_time
Select event_id from (SELECT event_id ,ROW_NUMBER() OVER(PARTITION BY event_id ORDER BY start_time desc) AS last_row FROM Rsvp) where last_row = 1
You can also use different Window Function as per your requirements.
Syntactic vs logical order of operations
I think that the confusion around the relationship between DISTINCT
and ORDER BY
(or also GROUP BY
, for that matter), can only really be understood if the logical order of operations in SQL is understood. It is different from the syntactic order of operations, which is the primary source of confusion.
In this example, it looks as though DISTINCT
is related to SELECT
, given its syntactic closeness, but it's really an operator that is applied after SELECT
(the projection). Due to the nature of what DISTINCT
does (remove duplicate rows), all the not-projected contents of a row are no longer available after the DISTINCT
operation, which includes the ORDER BY
clause. According to the logical order of operations (simplified):
-
FROM
(produces all possible column references) -
WHERE
(can use all column references fromFROM
) -
SELECT
(can use all column references fromFROM
, and create new expressions, and alias them) -
DISTINCT
(operates on the tuple projected bySELECT
) -
ORDER BY
(depending on the presence ofDISTINCT
, can operate on the tuple projected bySELECT
, and ifDISTINCT
is absent *perhaps (depending on the dialect) also on other expressions)
What about DISTINCT
and ORDER BY
The fact that, without DISTINCT
, ORDER BY
can access (in some dialects) also things that haven't been projected may be a bit weird, certainly useful. E.g. this works:
WITH emp (id, fname, name) AS (
VALUES (1, 'A', 'A'),
(2, 'C', 'A'),
(3, 'B', 'B')
)
SELECT id
FROM emp
ORDER BY fname DESC
dbfiddle here. Producing
id
--
2
3
1
This changes when you add DISTINCT
. This no longer works:
WITH emp (id, fname, name) AS (
VALUES (1, 'A', 'A'),
(2, 'C', 'A'),
(3, 'B', 'B')
)
SELECT DISTINCT name
FROM emp
ORDER BY fname DESC
dbfiddle here. The error being:
ERROR: for SELECT DISTINCT, ORDER BY expressions must appear in select list LINE 8: ORDER BY fname DESC
Because what fname
value would you attribute to name = A
? A
or C
? The answer would decide whether you'd be getting A
, B
as a result or B
, A
. It cannot be decided.
PostgreSQL DISTINCT ON
Now, as mentioned in the above linked article, PostgreSQL supports an exception to this, which can occasionally be useful: DISTINCT ON
(see also questions like these):
WITH emp (id, fname, name) AS (
VALUES (1, 'A', 'A'),
(2, 'C', 'A'),
(3, 'B', 'B')
)
SELECT DISTINCT ON (name) id, fname, name
FROM emp
ORDER BY name, fname, id
dbfiddle here, producing:
id |fname|name
---|-----|----
1 |A |A
3 |B |B
This query allows to produce only distinct values of name
, and then per duplicate row, take the first one given the ORDER BY
clause, which makes the choice per distinct group unambiguous. This can be emulated in other RDBMS using window functions.