How to Lazy Load div background images
As many of you know it is widely used to lazy load images.
Now i want to use this as lazy load div background images.
How can i do that ?
I am currently able to use http://www.appelsiini.net/projects/lazyload that plugin
So i need to modify it in a way that it will work with div backgrounds
Need help. Thank you.
The below part i suppose lazy loads images
$self.one("appear", function() {
if (!this.loaded) {
if (settings.appear) {
var elements_left = elements.length;
settings.appear.call(self, elements_left, settings);
}
$("<img />")
.bind("load", function() {
$self
.hide()
.attr("src", $self.data(settings.data_attribute))
[settings.effect](settings.effect_speed);
self.loaded = true;
/* Remove image from array so it is not looped next time. */
var temp = $.grep(elements, function(element) {
return !element.loaded;
});
elements = $(temp);
if (settings.load) {
var elements_left = elements.length;
settings.load.call(self, elements_left, settings);
}
})
.attr("src", $self.data(settings.data_attribute));
}
});
Jquery plugin lazy load
Solution 1:
First you need to think off when you want to swap. For example you could switch everytime when its a div tag thats loaded. In my example i just used a extra data field "background" and whenever its set the image is applied as a background image.
Then you just have to load the Data with the created image tag. And not overwrite the img tag instead apply a css background image.
Here is a example of the code change:
if (settings.appear) {
var elements_left = elements.length;
settings.appear.call(self, elements_left, settings);
}
var loadImgUri;
if($self.data("background"))
loadImgUri = $self.data("background");
else
loadImgUri = $self.data(settings.data_attribute);
$("<img />")
.bind("load", function() {
$self
.hide();
if($self.data("background")){
$self.css('backgroundImage', 'url('+$self.data("background")+')');
}else
$self.attr("src", $self.data(settings.data_attribute))
$self[settings.effect](settings.effect_speed);
self.loaded = true;
/* Remove image from array so it is not looped next time. */
var temp = $.grep(elements, function(element) {
return !element.loaded;
});
elements = $(temp);
if (settings.load) {
var elements_left = elements.length;
settings.load.call(self, elements_left, settings);
}
})
.attr("src", loadImgUri );
}
the loading stays the same
$("#divToLoad").lazyload();
and in this example you need to modify the html code like this:
<div data-background="http://apod.nasa.gov/apod/image/9712/orionfull_jcc_big.jpg" id="divToLoad" />
but it would also work if you change the switch to div tags and then you you could work with the "data-original" attribute.
Here's an fiddle example: http://jsfiddle.net/dtm3k/1/
Solution 2:
EDIT: the post from below is from 2012 and absolete by now!
I do it like this:
<div class="lazyload" style="width: 1000px; height: 600px" data-src="%s">
<img class="spinner" src="spinner.gif"/>
</div>
and load with
$(window).load(function(){
$('.lazyload').each(function() {
var lazy = $(this);
var src = lazy.attr('data-src');
$('<img>').attr('src', src).load(function(){
lazy.find('img.spinner').remove();
lazy.css('background-image', 'url("'+src+'")');
});
});
});
Solution 3:
I've found this on the plugin's official site:
<div class="lazy" data-original="img/bmw_m1_hood.jpg" style="background-image: url('img/grey.gif'); width: 765px; height: 574px;"></div>
$("div.lazy").lazyload({
effect : "fadeIn"
});
Source: http://www.appelsiini.net/projects/lazyload/enabled_background.html