If list index exists, do X
Could it be more useful for you to use the length of the list len(n)
to inform your decision rather than checking n[i]
for each possible length?
I need to code such that if a certain list index exists, then run a function.
This is the perfect use for a try block:
ar=[1,2,3]
try:
t=ar[5]
except IndexError:
print('sorry, no 5')
# Note: this only is a valid test in this context
# with absolute (ie, positive) index
# a relative index is only showing you that a value can be returned
# from that relative index from the end of the list...
However, by definition, all items in a Python list between 0
and len(the_list)-1
exist (i.e., there is no need for a try block if you know 0 <= index < len(the_list)
).
You can use enumerate if you want the indexes between 0 and the last element:
names=['barney','fred','dino']
for i, name in enumerate(names):
print(i + ' ' + name)
if i in (3,4):
# do your thing with the index 'i' or value 'name' for each item...
If you are looking for some defined 'index' though, I think you are asking the wrong question. Perhaps you should consider using a mapping container (such as a dict) versus a sequence container (such as a list). You could rewrite your code like this:
def do_something(name):
print('some thing 1 done with ' + name)
def do_something_else(name):
print('something 2 done with ' + name)
def default(name):
print('nothing done with ' + name)
something_to_do={
3: do_something,
4: do_something_else
}
n = input ("Define number of actors: ")
count = 0
names = []
for count in range(n):
print("Define name for actor {}:".format(count+1))
name = raw_input ()
names.append(name)
for name in names:
try:
something_to_do[len(name)](name)
except KeyError:
default(name)
Runs like this:
Define number of actors: 3
Define name for actor 1: bob
Define name for actor 2: tony
Define name for actor 3: alice
some thing 1 done with bob
something 2 done with tony
nothing done with alice
You can also use .get method rather than try/except for a shorter version:
>>> something_to_do.get(3, default)('bob')
some thing 1 done with bob
>>> something_to_do.get(22, default)('alice')
nothing done with alice