Any way to reset a mocked method to its original state? - Python Mock - mock 1.0b1
Solution 1:
You can use mock.patch
as a decorator or a context manager:
from mock import patch, MagicMock
@patch('myClass.A', MagicMock(return_value='CPU'))
def test(self):
pass
or:
def test(self):
with patch('myClass.A', MagicMock(return_value='CPU')):
pass
If you don't supply a mock object to patch
then it will provide an autospecced mock that you can modify:
@patch('myClass.A')
def test(self, mock_A):
mock_A.return_value = 'CPU'
pass
or:
def test(self):
with patch('myClass.A') as mock_A:
mock_A.return_value = 'CPU'
pass
In all cases the original value will be restored when the decorated test function or context manager finishes.
Solution 2:
You can stash the function away on self and put it back when you're done.
import unittest
from mock import MagicMock
from MyClass import MyClass
class FirstTest(unittest.TestCase):
def setUp(self):
self.A = MyClass.A
MyClass.A = MagicMock(name='mocked A', return_value='CPU')
def tearDown(self):
MyClass.A = self.A
def test_mocked_static_method(self):
print 'First Test'
print MyClass.check
print MyClass.A
class SecondTest(unittest.TestCase):
def setUp(self):
MyClass.check = MagicMock(name='mocked check', return_value=object)
def test_check_mocked_check_method(self):
print 'Second Test'
print MyClass.check
print MyClass.A
if __name__ == '__main__':
unittest.main()
Running this file gives the following output:
First Test
<unbound method MyClass.check>
<MagicMock name='mocked A' id='141382732'>
Second Test
<MagicMock name='mocked check' id='141382860'>
<unbound method MyClass.A>
I found myself using the patch decorator a lot more than setUp and tearDown now. In this case you could do
from mock import patch
@patch('MyClass.A')
def test_mocked_static_method(self, mocked_A)
mocked_A.return_value = 'CPU'
# This mock will expire when the test method is finished