Retrieving Data from SQL Using pyodbc
I am trying to retrieve data from an SQL server using pyodbc and print it in a table using Python. However, I can only seem to retrieve the column name and the data type and stuff like that, not the actual data values in each row of the column.
Basically I am trying to replicate an Excel sheet that retrieves server data and displays it in a table. I am not having any trouble connecting to the server, just that I can't seem to find the actual data that goes into the table.
Here is an example of my code:
import pyodbc
cnxn = pyodbc.connect('DRIVER={SQL Server};SERVER=SQLSRV01;DATABASE=DATABASE;UID=USER;PWD=PASSWORD')
cursor = cnxn.cursor()
cursor.execute("SELECT * FROM sys.tables")
tables = cursor.fetchall()
#cursor.execute("SELECT WORK_ORDER.TYPE,WORK_ORDER.STATUS, WORK_ORDER.BASE_ID, WORK_ORDER.LOT_ID FROM WORK_ORDER")
for row in cursor.columns(table='WORK_ORDER'):
print row.column_name
for field in row:
print field
However the result of this just gives me things like the table name, the column names, and some integers and 'None's and things like that that aren't of interest to me:
STATUS_EFF_DATE
DATABASE
dbo
WORK_ORDER
STATUS_EFF_DATE
93
datetime
23
16
3
None
0
None
None
9
3
None
80
NO
61
So I'm not really sure where I can get the values to fill up my table. Would it should be in table='WORK_ORDER', but could it be under a different table name? Is there a way of printing the data that I am just missing?
Any advice or suggestions would be greatly appreciated.
You are so close!
import pyodbc
cnxn = pyodbc.connect('DRIVER={SQL Server};SERVER=SQLSRV01;DATABASE=DATABASE;UID=USER;PWD=PASSWORD')
cursor = cnxn.cursor()
cursor.execute("SELECT WORK_ORDER.TYPE,WORK_ORDER.STATUS, WORK_ORDER.BASE_ID, WORK_ORDER.LOT_ID FROM WORK_ORDER")
for row in cursor.fetchall():
print row
(the "columns()" function collects meta-data about the columns in the named table, as opposed to the actual data).
In order to receive actual data stored in the table, you should use one of fetch...() functions or use the cursor as an iterator (i.e. "for row in cursor"...). This is described in the documentation:
cursor.execute("select user_id, user_name from users where user_id < 100")
rows = cursor.fetchall()
for row in rows:
print row.user_id, row.user_name
you could try using Pandas to retrieve information and get it as dataframe
import pyodbc as cnn
import pandas as pd
cnxn = pyodbc.connect('DRIVER={SQL Server};SERVER=SQLSRV01;DATABASE=DATABASE;UID=USER;PWD=PASSWORD')
# Copy to Clipboard for paste in Excel sheet
def copia (argumento):
df=pd.DataFrame(argumento)
df.to_clipboard(index=False,header=True)
tableResult = pd.read_sql("SELECT * FROM YOURTABLE", cnxn)
# Copy to Clipboard
copia(tableResult)
# Or create a Excel file with the results
df=pd.DataFrame(tableResult)
df.to_excel("FileExample.xlsx",sheet_name='Results')
I hope this helps! Cheers!
Instead of using the pyodbc library, use the pypyodbc library... This worked for me.
import pypyodbc
conn = pypyodbc.connect("DRIVER={SQL Server};"
"SERVER=server;"
"DATABASE=database;"
"Trusted_Connection=yes;")
cursor = conn.cursor()
cursor.execute('SELECT * FROM [table]')
for row in cursor:
print('row = %r' % (row,))
Just do this:
import pandas as pd
import pyodbc
cnxn = pyodbc.connect("Driver={SQL Server}\
;Server=SERVER_NAME\
;Database=DATABASE_NAME\
;Trusted_Connection=yes")
df = pd.read_sql("SELECT * FROM myTableName", cnxn)
df.head()