use a javascript array to fill up a drop down select box
I have a text file which I am reading and storing the data in a javascript array, it's a list of cuisines. I want to use the array to fill up a drop down select box. I know how to hard code in the values for the drop down box (using correct me if i'm wrong) but I want to be able to use the array to fill it up instead.
<script type="text/javascript">
var cuisines = ["Chinese","Indian"];
</script>
<select id="CusineList"></select>
I have hard coded an array for simplicity, the "CuisineList" is my drop down box
Solution 1:
Use a for
loop to iterate through your array. For each string, create a new option
element, assign the string as its innerHTML
and value
, and then append it to the select
element.
var cuisines = ["Chinese","Indian"];
var sel = document.getElementById('CuisineList');
for(var i = 0; i < cuisines.length; i++) {
var opt = document.createElement('option');
opt.innerHTML = cuisines[i];
opt.value = cuisines[i];
sel.appendChild(opt);
}
DEMO
UPDATE: Using createDocumentFragment
and forEach
If you have a very large list of elements that you want to append to a document, it can be non-performant to append each new element individually. The DocumentFragment
acts as a light weight document object that can be used to collect elements. Once all your elements are ready, you can execute a single appendChild
operation so that the DOM only updates once, instead of n
times.
var cuisines = ["Chinese","Indian"];
var sel = document.getElementById('CuisineList');
var fragment = document.createDocumentFragment();
cuisines.forEach(function(cuisine, index) {
var opt = document.createElement('option');
opt.innerHTML = cuisine;
opt.value = cuisine;
fragment.appendChild(opt);
});
sel.appendChild(fragment);
DEMO
Solution 2:
This is a part from a REST-Service I´ve written recently.
var select = $("#productSelect")
for (var prop in data) {
var option = document.createElement('option');
option.innerHTML = data[prop].ProduktName
option.value = data[prop].ProduktName;
select.append(option)
}
The reason why im posting this is because appendChild() wasn´t working in my case so I decided to put up another possibility that works aswell.