How to convert a string with Unicode encoding to a string of letters

Solution 1:

The Apache Commons Lang StringEscapeUtils.unescapeJava() can decode it properly.

import org.apache.commons.lang.StringEscapeUtils;

@Test
public void testUnescapeJava() {
    String sJava="\\u0048\\u0065\\u006C\\u006C\\u006F";
    System.out.println("StringEscapeUtils.unescapeJava(sJava):\n" + StringEscapeUtils.unescapeJava(sJava));
}


 output:
 StringEscapeUtils.unescapeJava(sJava):
 Hello

Solution 2:

Technically doing:

String myString = "\u0048\u0065\u006C\u006C\u006F World";

automatically converts it to "Hello World", so I assume you are reading in the string from some file. In order to convert it to "Hello" you'll have to parse the text into the separate unicode digits, (take the \uXXXX and just get XXXX) then do Integer.ParseInt(XXXX, 16) to get a hex value and then case that to char to get the actual character.

Edit: Some code to accomplish this:

String str = myString.split(" ")[0];
str = str.replace("\\","");
String[] arr = str.split("u");
String text = "";
for(int i = 1; i < arr.length; i++){
    int hexVal = Integer.parseInt(arr[i], 16);
    text += (char)hexVal;
}
// Text will now have Hello

Solution 3:

You can use StringEscapeUtils from Apache Commons Lang, i.e.:

String Title = StringEscapeUtils.unescapeJava("\\u0048\\u0065\\u006C\\u006C\\u006F");

Solution 4:

This simple method will work for most cases, but would trip up over something like "u005Cu005C" which should decode to the string "\u0048" but would actually decode "H" as the first pass produces "\u0048" as the working string which then gets processed again by the while loop.

static final String decode(final String in)
{
    String working = in;
    int index;
    index = working.indexOf("\\u");
    while(index > -1)
    {
        int length = working.length();
        if(index > (length-6))break;
        int numStart = index + 2;
        int numFinish = numStart + 4;
        String substring = working.substring(numStart, numFinish);
        int number = Integer.parseInt(substring,16);
        String stringStart = working.substring(0, index);
        String stringEnd   = working.substring(numFinish);
        working = stringStart + ((char)number) + stringEnd;
        index = working.indexOf("\\u");
    }
    return working;
}

Solution 5:

Shorter version:

public static String unescapeJava(String escaped) {
    if(escaped.indexOf("\\u")==-1)
        return escaped;

    String processed="";

    int position=escaped.indexOf("\\u");
    while(position!=-1) {
        if(position!=0)
            processed+=escaped.substring(0,position);
        String token=escaped.substring(position+2,position+6);
        escaped=escaped.substring(position+6);
        processed+=(char)Integer.parseInt(token,16);
        position=escaped.indexOf("\\u");
    }
    processed+=escaped;

    return processed;
}