Open a link in browser with java button? [duplicate]

How can I open a link in default browser with a button click, along the lines of

button.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e) {
        open("www.google.com"); // just what is the 'open' method?
    }
});

?

Use the Desktop#browse(URI) method. It opens a URI in the user's default browser.

public static boolean openWebpage(URI uri) {
    Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;
    if (desktop != null && desktop.isSupported(Desktop.Action.BROWSE)) {
        try {
            desktop.browse(uri);
            return true;
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
    return false;
}

public static boolean openWebpage(URL url) {
    try {
        return openWebpage(url.toURI());
    } catch (URISyntaxException e) {
        e.printStackTrace();
    }
    return false;
}

public static void openWebpage(String urlString) {
    try {
        Desktop.getDesktop().browse(new URL(urlString).toURI());
    } catch (Exception e) {
        e.printStackTrace();
    }
}

try {
    Desktop.getDesktop().browse(new URL("http://www.google.com").toURI());
} catch (Exception e) {}

note: you have to include necessary imports from java.net

A solution without the Desktop environment is BrowserLauncher2. This solution is more general as on Linux, Desktop is not always available.

The lenghty answer is posted at https://stackoverflow.com/a/21676290/873282