How can I grep hidden files?

Solution 1:

Please refer to the solution at the end of this post as a better alternative to what you're doing.

You can explicitly include hidden files (a directory is also a file).

grep -r search * .[^.]*

The * will match all files except hidden ones and .[^.]* will match only hidden files without ... However this will fail if there are either no non-hidden files or no hidden files in a given directory. You could of course explicitly add .git instead of .*.

However, if you simply want to search in a given directory, do it like this:

grep -r search .

The . will match the current path, which will include both non-hidden and hidden files.

Solution 2:

I just ran into this problem, and based on @bitmask's answer, here is my simple modification to avoid the problem pointed out by @sehe:

grep -r search_string * .[^.]*

Solution 3:

Perhaps you will prefer to combine "grep" with the "find" command for a complete solution like:

find . -exec grep -Hn search {} \;

This command will search inside hidden files or directories for string "search" and list any files with a coincidence with this output format:

File path:Line number:line with coincidence

./foo/bar:42:search line
./foo/.bar:42:search line
./.foo/bar:42:search line
./.foo/.bar:42:search line

Solution 4:

You may want to use this approach, assuming you're searching the current directory (otherwise replace . with the desired directory):

find . -type f | xargs grep search

or if you just want to search at the top level (which is quicker to test if you're trying these out):

find . -type f -maxdepth 1 | xargs grep search

UPDATE: I modified the examples in response to Scott's comments. I also added "-type f".

Solution 5:

To prevent matching . and .. which are not hidden files, you can use grep with ls -A like in this example:

ls -A | grep "^\."

^\. states that the first character must be .

The -A or --almost-all option excludes the results . and .. so that only hidden files and directories are matched.