Split string on the first white space occurrence

Solution 1:

If you only care about the space character (and not tabs or other whitespace characters) and only care about everything before the first space and everything after the first space, you can do it without a regular expression like this:

str.substr(0,str.indexOf(' ')); // "72"
str.substr(str.indexOf(' ')+1); // "tocirah sneab"

Note that if there is no space at all, then the first line will return an empty string and the second line will return the entire string. Be sure that is the behavior that you want in that situation (or that that situation will not arise).

Somewhat pedantic update: Although it is supported in effectively all browsers as well as Node.js, deno, etc., String.prototype.substr() has never been added normatively to the ECMAScript spec. Practically, this is unlikely to affect you. However, if it bothers you (or if you are running in some resource-constrained environment that doesn't have String.prototype.substr() for some reason), you can use one of the many other fine answers people have provided on this question. String.prototype.slice() is a pretty good substitute but be careful of the weirdness that ensues if indexOf() returns -1 for the second argument to slice(). (It will truncate the last character of the string.) Personally, I like the regexp lookbehind solution at the end of @georg's answer, but that won't work for very old browsers, so be aware of that.

Solution 2:

Javascript doesn't support lookbehinds, so split is not possible. match works:

str.match(/^(\S+)\s(.*)/).slice(1)

Another trick:

str.replace(/\s+/, '\x01').split('\x01')

how about:

[str.replace(/\s.*/, ''), str.replace(/\S+\s/, '')]

and why not

reverse = function (s) { return s.split('').reverse().join('') }
reverse(str).split(/\s(?=\S+$)/).reverse().map(reverse)

or maybe

re = /^\S+\s|.*/g;
[].concat.call(re.exec(str), re.exec(str))

2019 update: as of ES2018, lookbehinds are supported:

str = "72 tocirah sneab"
s = str.split(/(?<=^\S+)\s/)
console.log(s)

Solution 3:

In ES6 you can also

let [first, ...second] = str.split(" ")
second = second.join(" ")