How to SELECT based on value of another SELECT

I have a table that looks something like this:

Name    Year   Value
 A      2000     5
 A      2001     3
 A      2002     7
 A      2003     1
 B      2000     6
 B      2001     1
 B      2002     8
 B      2003     2

The user can query based on a range of years, and it will return the sum of Value grouped by Name, as such (assume queried years are 2000 - 2001):

Name   SUM(Value)
 A         8
 B         7

Now, I wanted to insert a calculated field that outputs the ratio of the sum of the values of each name for ALL years to the sum of all values. Basically the percentage of all values attributed to A and B, respectively, like:

Name   SUM(Value)   % Of Total
 A         8            0.484      (16 / 33)
 B         7            0.516      (17 / 33)

Note that even though the user queried only 2000-2001, I want the calculation to use the sum across all years. I've been searching and experimenting for hours and I cannot figure out how. I only know how to sum across the queried years like so:

SELECT `Name`, SUM(`Value`)/(SELECT SUM(`Value`) FROM `table1`) AS "% of Total"
FROM `table1`
WHERE `Year` BETWEEN 2000 AND 2001
GROUP BY `Name`;

You can calculate the total (and from that the desired percentage) by using a subquery in the FROM clause:

SELECT Name,
       SUM(Value) AS "SUM(VALUE)",
       SUM(Value) / totals.total AS "% of Total"
FROM   table1,
       (
           SELECT Name,
                  SUM(Value) AS total
           FROM   table1
           GROUP BY Name
       ) AS totals
WHERE  table1.Name = totals.Name
AND    Year BETWEEN 2000 AND 2001
GROUP BY Name;

Note that the subquery does not have the WHERE clause filtering the years.

If you want to SELECT based on the value of another SELECT, then you probably want a "subselect":

http://beginner-sql-tutorial.com/sql-subquery.htm

For example, (from the link above):

1. You want the first and last names from table "student_details" ...

2. But you only want this information for those students in "science" class:

    SELECT id, first_name
    FROM student_details
    WHERE first_name IN (SELECT first_name
    FROM student_details
    WHERE subject= 'Science'); 
   

Frankly, I'm not sure this is what you're looking for or not ... but I hope it helps ... at least a little...

IMHO...

SELECT x.name, x.summary, (x.summary / COUNT(*)) as percents_of_total
FROM tbl t
INNER JOIN 
(SELECT name, SUM(value) as summary
FROM tbl
WHERE year BETWEEN 2000 AND 2001
GROUP BY name) x ON x.name = t.name
GROUP BY x.name, x.summary