Remove object from a list of objects in python

In python there are no arrays, lists are used instead. There are various ways to delete an object from a list:

my_list = [1,2,4,6,7]

del my_list[1] # Removes index 1 from the list
print my_list # [1,4,6,7]
my_list.remove(4) # Removes the integer 4 from the list, not the index 4
print my_list # [1,6,7]
my_list.pop(2) # Removes index 2 from the list

In your case the appropriate method to use is pop, because it takes the index to be removed:

x = object()
y = object()
array = [x, y]
array.pop(0)
# Using the del statement
del array[0]

del array[0]

where 0 is the index of the object in the list (there is no array in python)

If you want to remove multiple object from a list. There are various ways to delete an object from a list

Try this code. a is list with all object, b is list object you want to remove.

example :

a = [1,2,3,4,5,6]
b = [2,3]

for i in b:
   if i in a:
      a.remove(i)

print(a)

the output is [1,4,5,6] I hope, it will work for you

You could try this to dynamically remove an object from an array without looping through it? Where e and t are just random objects.

>>> e = {'b':1, 'w': 2}
>>> t = {'b':1, 'w': 3}
>>> p = [e,t]
>>> p
[{'b': 1, 'w': 2}, {'b': 1, 'w': 3}]
>>>
>>> p.pop(p.index({'b':1, 'w': 3}))
{'b': 1, 'w': 3}
>>> p
[{'b': 1, 'w': 2}]
>>>