How to get the sizes of the tables of a MySQL database?
You can use this query to show the size of a table (although you need to substitute the variables first):
SELECT
table_name AS `Table`,
round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB`
FROM information_schema.TABLES
WHERE table_schema = "$DB_NAME"
AND table_name = "$TABLE_NAME";
or this query to list the size of every table in every database, largest first:
SELECT
table_schema as `Database`,
table_name AS `Table`,
round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB`
FROM information_schema.TABLES
ORDER BY (data_length + index_length) DESC;
SELECT TABLE_NAME AS "Table Name",
table_rows AS "Quant of Rows", ROUND( (
data_length + index_length
) /1024, 2 ) AS "Total Size Kb"
FROM information_schema.TABLES
WHERE information_schema.TABLES.table_schema = 'YOUR SCHEMA NAME/DATABASE NAME HERE'
LIMIT 0 , 30
You can get schema name from "information_schema" -> SCHEMATA table -> "SCHEMA_NAME" column
Additional You can get size of the mysql databases as following.
SELECT table_schema "DB Name",
Round(Sum(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB"
FROM information_schema.tables
GROUP BY table_schema
ORDER BY `DB Size in MB` DESC;
Result
DB Name | DB Size in MB
mydatabase_wrdp 39.1
information_schema 0.0
You can get additional details in here.
SELECT
table_name AS "Table",
round(((data_length + index_length) / 1024 / 1024), 2) as size
FROM information_schema.TABLES
WHERE table_schema = "YOUR_DATABASE_NAME"
ORDER BY size DESC;
This sorts the sizes (DB Size in MB).
If you want a query to use currently selected database. simply copy paste this query. (No modification required)
SELECT table_name ,
round(((data_length + index_length) / 1024 / 1024), 2) as SIZE_MB
FROM information_schema.TABLES
WHERE table_schema = DATABASE() ORDER BY SIZE_MB DESC;
-
Size of all tables:
Suppose your database or
TABLE_SCHEMA
name is "news_alert". Then this query will show the size of all tables in the database.SELECT TABLE_NAME AS `Table`, ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024),2) AS `Size (MB)` FROM information_schema.TABLES WHERE TABLE_SCHEMA = "news_alert" ORDER BY (DATA_LENGTH + INDEX_LENGTH) DESC;
Output:
+---------+-----------+ | Table | Size (MB) | +---------+-----------+ | news | 0.08 | | keyword | 0.02 | +---------+-----------+ 2 rows in set (0.00 sec)
-
For the specific table:
Suppose your
TABLE_NAME
is "news". Then SQL query will be-SELECT TABLE_NAME AS `Table`, ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024),2) AS `Size (MB)` FROM information_schema.TABLES WHERE TABLE_SCHEMA = "news_alert" AND TABLE_NAME = "news" ORDER BY (DATA_LENGTH + INDEX_LENGTH) DESC;
Output:
+-------+-----------+ | Table | Size (MB) | +-------+-----------+ | news | 0.08 | +-------+-----------+ 1 row in set (0.00 sec)