Logical operator || in javascript, 0 stands for Boolean false?
Solution 1:
-
||
—expr1 || expr2
(Logical OR)Returns expr1 if it can be converted to true; otherwise, returns expr2. Thus, when used with Boolean values, || returns true if either operand is true; if both are false, returns false..
-
&&
—expr1 && expr2
(Logical AND)Returns expr1 if it can be converted to false; otherwise, returns expr2. Thus, when used with Boolean values, && returns true if both operands are true; otherwise, returns false.
All values in Javascript are either "truthy" or "falsy".
The following values are equivalent to false in conditional statements:
- false
- null
- undefined
- The empty string
""
(\''
) - The number 0
- The number NaN
All other values are equivalent to true.
So... var test = 0 || -1 ;
returns -1
.
If it was var test = 0 || false || undefined || "" || 2 || -1
it would return 2
Logical operator on MDN
Solution 2:
You can use Nullish coalescing operator (??)
The nullish coalescing operator (??) is a logical operator that returns its right-hand side operand when its left-hand side operand is null or undefined, and otherwise returns its left-hand side operand.
Only null and undefined will be falsey. 0 will be considered true. But take care: an empty string will be considered true too!
console.log('0 ?? 1 ->', 0 ?? 1) // expected output: 0
console.log('null ?? 1 -> ', null ?? 1) // expected output: 1
console.log('undefined ?? 1 ->', undefined ?? 1) // expected output: 1
console.log('"" ?? 1 ->', "" ?? 1) // expected output: ""