Why inner class can override private final method?

I wondered if it makes sense to declare a private method as final as well, and I thought it doesn't make sense. But I imagined there's an exclusive situation and wrote the code to figure it out:

public class Boom {

    private void touchMe() {
        System.out.println("super::I am not overridable!");
    }

    private class Inner extends Boom {

        private void touchMe() {
            super.touchMe();
            System.out.println("sub::You suck! I overrided you!");
        }
    }

    public static void main(String... args) {
        Boom boom = new Boom();
        Boom.Inner inner = boom.new Inner();
        inner.touchMe();
    }
}

It compiled and worked. "I should make touchMe() final" I thought and did it:

public class Boom {

    private final void touchMe() {
        System.out.println("super::I am not overridable!");
    }

    private class Inner extends Boom {

        private void touchMe() {
            super.touchMe();
            System.out.println("sub::You suck! I overrided you!");
        }
    }

    public static void main(String... args) {
        Boom boom = new Boom();
        Boom.Inner inner = boom.new Inner();
        inner.touchMe();
    }
}

and it also works and tells me

chicout@chicout-linlap:~$ java Boom
super::I am not overridable!
sub::You suck! I overrided you!

why?

Private methods can not be overridden (private methods are not inherited!) In fact, it makes no difference if you declare a private method final or not.

The two methods you have declared, Boom.touchMe and Boom.Inner.touchMe are two completely separate methods which just happen to share the same identifier. The fact that super.touchMe refers to a different method than touchMe, is just because Boom.Inner.touchMe shadows Boom.touchMe (and not because it overrides it).

This can be demonstrated in a number of ways:

As you discovered yourself, if you change the methods to be public, the compiler will complain because you are suddenly trying to override a final method.
If you keep the methods private and add the @Override annotation, the compiler will complain.
As alpian points out, if you cast the Boom.Inner object to a Boom object (((Boom) inner).touchMe()) the Boom.touchMe is called (if it indeed was overridden, the cast wouldn't matter).

Related question:

Make private methods final?

I think the fact that there really are two separate methods here is nicely demonstrated by changing your main as follows:

public static void main(String... args) {
    Boom boom = new Boom();
    Boom.Inner inner = boom.new Inner();
    inner.touchMe();
    System.out.println("And now cast it...");
    ((Boom)(inner)).touchMe();
}

This now prints:

super::I am not overridable!
sub::You suck! I overrided you!
And now cast it...
super::I am not overridable!

And the reason that the call to super works in Inner is because you're looking up a method called touchMe in your super-class (Boom) which indeed exists and is visible to Inner as it is in the same class.

Why inner class can override private final method?

Related

Recent Posts