Request string without GET arguments [duplicate]
Edit: @T.Todua provided a newer answer to this question using parse_url.
(please upvote that answer so it can be more visible).
Edit2: Someone has been spamming and editing about extracting scheme, so I've added that at the bottom.
parse_url solution
The simplest solution would be:
echo parse_url($_SERVER["REQUEST_URI"], PHP_URL_PATH);
Parse_url is a built-in php function, who's sole purpose is to extract specific components from a url, including the PATH
(everything before the first ?
). As such, it is my new "best" solution to this problem.
strtok solution
Stackoverflow: How to remove the querystring and get only the url?
You can use strtok to get string before first occurence of ?
$url=strtok($_SERVER["REQUEST_URI"],'?');
Performance Note: This problem can also be solved using explode.
- Explode tends to perform better for cases splitting the sring only on a single delimiter.
- Strtok tends to perform better for cases utilizing multiple delimiters.
This application of strtok to return everything in a string before the first instance of a character will perform better than any other method in PHP, though WILL leave the querystring in memory.
An aside about Scheme (http/https) and $_SERVER
vars
While OP did not ask about it, I suppose it is worth mentioning: parse_url should be used to extract any specific component from the url, please see the documentation for that function:
parse_url($actual_link, PHP_URL_SCHEME);
Of note here, is that getting the full URL from a request is not a trivial task, and has many security implications. $_SERVER
variables are your friend here, but they're a fickle friend, as apache/nginx configs, php environments, and even clients, can omit or alter these variables. All of this is well out of scope for this question, but it has been thoroughly discussed:
https://stackoverflow.com/a/6768831/1589379
It is important to note that these $_SERVER
variables are populated at runtime, by whichever engine is doing the execution (/var/run/php/
or /etc/php/[version]/fpm/
). These variables are passed from the OS, to the webserver (apache/nginx) to the php engine, and are modified and amended at each step. The only such variables that can be relied on are REQUEST_URI
(because it's required by php), and those listed in RFC 3875 (see: PHP: $_SERVER ) because they are required of webservers.
please note: spaming links to your answers across other questions is not in good taste.
You can use $_SERVER['REQUEST_URI']
to get requested path. Then, you'll need to remove the parameters...
$uri_parts = explode('?', $_SERVER['REQUEST_URI'], 2);
Then, add in the hostname and protocol.
echo 'http://' . $_SERVER['HTTP_HOST'] . $uri_parts[0];
You'll have to detect protocol as well, if you mix http:
and https://
. That I leave as an exercise for you. $_SERVER['REQUEST_SCHEME']
returns the protocol.
Putting it all together:
echo $_SERVER['REQUEST_SCHEME'] .'://'. $_SERVER['HTTP_HOST'] . explode('?', $_SERVER['REQUEST_URI'], 2)[0];
...returns, for example:
http://example.com/directory/file.php
php.com Documentation:
-
$_SERVER
— Server and execution environment information -
explode
— Split a string by a string -
parse_url
— Parse a URL and return its components (possibly a better solution)
Solution:
echo
parse_url
($_SERVER["REQUEST_URI"], PHP_URL_PATH);
Here is a solution that takes into account different ports and https:
$pageURL = (@$_SERVER['HTTPS'] == 'on') ? 'https://' : 'http://';
if ($_SERVER['SERVER_PORT'] != '80')
$pageURL .= $_SERVER['SERVER_NAME'].':'.$_SERVER['SERVER_PORT'].$_SERVER['PHP_SELF'];
else
$pageURL .= $_SERVER['SERVER_NAME'].$_SERVER['PHP_SELF'];
Or a more basic solution that does not take other ports into account:
$pageURL = (@$_SERVER['HTTPS'] == 'on') ? 'https://' : 'http://';
$pageURL .= $_SERVER['SERVER_NAME'].$_SERVER['PHP_SELF'];