Convert string into Date type on Python [duplicate]

I have this string:

'2012-02-10' # (year-month-day)

and I need it to be as date type for me to use the date function isoweekday().

Does anyone know how I can convert this string into a date?

While it seems the question was answered per the OP's request, none of the answers give a good way to get a datetime.date object instead of a datetime.datetime. So for those searching and finding this thread:

datetime.date has no .strptime method; use the one on datetime.datetime instead and then call .date() on it to receive the datetime.date object.

Like so:

>>> from datetime import datetime
>>> datetime.strptime('2014-12-04', '%Y-%m-%d').date()
datetime.date(2014, 12, 4)

You can do that with datetime.strptime()

Example:

>>> from datetime import datetime
>>> datetime.strptime('2012-02-10' , '%Y-%m-%d')
datetime.datetime(2012, 2, 10, 0, 0)
>>> _.isoweekday()
5

You can find the table with all the strptime directive here.

To increment by 2 days if .isweekday() == 6, you can use timedelta():

>>> import datetime
>>> date = datetime.datetime.strptime('2012-02-11' , '%Y-%m-%d')
>>> if date.isoweekday() == 6:
...     date += datetime.timedelta(days=2)
... 
>>> date
datetime.datetime(2012, 2, 13, 0, 0)
>>> date.strftime('%Y-%m-%d')   # if you want a string again
'2012-02-13'

from datetime import datetime

a = datetime.strptime(f, "%Y-%m-%d")

Use datetime.datetime.strptime:

>>> import datetime
>>> date = datetime.datetime.strptime('2012-02-10', '%Y-%m-%d')
>>> date.isoweekday()
5