how to compare the Java Byte[] array?

public class ByteArr {

    public static void main(String[] args){
        Byte[] a = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00};
        Byte[] b = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00};
        byte[] aa = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00};
        byte[] bb = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00};

        System.out.println(a);
        System.out.println(b);
        System.out.println(a == b);
        System.out.println(a.equals(b));

        System.out.println(aa);
        System.out.println(bb);
        System.out.println(aa == bb);
        System.out.println(aa.equals(bb));
    }
}

I do not know why all of them print false.

When I run "java ByteArray", the answer is "false false false false".

I think the a[] equals b[] but the JVM is telling me I am wrong, why？？

Solution 1:

Use Arrays.equals() if you want to compare the actual content of arrays that contain primitive types values (like byte).

System.out.println(Arrays.equals(aa, bb));

Use Arrays.deepEquals for comparison of arrays that contain objects.

Solution 2:

Cause they're not equal, ie: they're different arrays with equal elements inside.

Try using Arrays.equals() or Arrays.deepEquals().

Solution 3:

As byte[] is mutable it is treated as only being .equals() if its the same object.

If you want to compare the contents you have to use Arrays.equals(a, b)

BTW: Its not the way I would design it. ;)

Solution 4:

have you looked at Arrays.equals()?

Edit: if, as per your comment, the issue is using a byte array as a HashMap key then see this question.