Getting max value from rows and joining to another table

Sorry if this is being stupid, I am really a newbie trying to nail this.

Table A:
ID  Rank Name
1   100  Name1
1    45  Name2
2    60  Name3
2    42  Name4
2    88 Name5

Table B:
ID FileName
1  fn1
2  fn2

What I want is

1 fn1 name1
2 fn2 name5

This is what my query looks like, but it gives me multiple rows of results (instead of max) when i do the join

select B.Id B.FileName,A.Name
FRom B
JOIN ( 
select A.Id, MAX(A.Rank)as ExpertRank 
from A 
group by A.Id
) as NewA on A.Id = B.ID 
join B on A.Rank = NewA.Rank

Sub-query works fine, I get the problem on doing th join.

How do I fix this?

Thanks.

I have sql server 2008 R2

Last one is what I missed.

select B.Id B.FileName,A.Name 
FRom B 
JOIN (  
select A.Id, MAX(A.Rank)as ExpertRank  
from A  
group by A.Id 
) as NewA on A.Id = B.ID  
join B on A.Rank = NewA.Rank 
and A.Id = newA.Id

Solution 1:

What you wrote was missing A in the from clause so its not entirely clear where you went wrong but this should work

select 
       B.Id, 
       B.FileName,
       A.Name
FRom B
     INNER JOIN A
     ON A.id = B.id
    INNER JOIN ( 
          select A.Id, MAX(A.Rank)as ExpertRank 
          from A 
          group by A.Id
     ) as NewA 
    ON a.Id = NewA.ID 
       AND a.Rank = NewA.ExpertRank

See it working here

Alternatively you could use rownumber instead

WITH CTE AS 
(
   SELECT ID, 
          RANK,
          Name,
          ROW_NUMBER() OVER (PARTITION BY ID ORDER BY RANK DESC) rn
   FROM A
)
SELECT b.Id b.FileName,cte.Name
FROM
   b
   INNER JOIN cte 
   ON b.id = cte.id
      and cte.rn = 1

See it working here

Solution 2:

Here's an answer with JOINs instead of MAX():

SELECT DISTINCT b.id, b.filename, a1.name
FROM a a1
JOIN b
  ON b.id = a1.id
LEFT JOIN a a2
  ON a2.id = a1.id
  AND a2.rank > a1.rank
WHERE a2.id IS NULL

If there are no duplicate ranks for the same id, then you don't need the DISTINCT.