Sort CSV file by column priority using the "sort" command

I have a csv file, and I would like to sort it by column priority, like "order by". For example:

3;1;2
1;3;2
1;2;3
2;3;1
2;1;3
3;2;1

If this situation was the result of a "select", the "order by" would be as follows: order by column2, column1, column3 - the result would be:

2;1;3
3;1;2
1;2;3
3;2;1
1;3;2
2;3;1

I'd like to know how to get this same result using "sort" command on Unix.

Solution 1:

sort --field-separator=';' --key=2,1,3

Solution 2:

Suppose you have another row 3;10;3 in your unsorted.csv file. Then I guess you expect a numerically sorted result:

2;1;3
3;1;2
1;2;3
3;2;1
1;3;2
2;3;1
3;10;3

and not an alphabetically sorted one:

2;1;3
3;1;2
3;10;3
1;2;3
3;2;1
1;3;2
2;3;1

To get that, you have to use -n:

sort --field-separator=';' -n -k 2,2 -k 1,1 -k 3,3 unsorted.csv

It is worth mentioning that 2,2 has to be used. If only 2 is used, then sort takes the string from beginning of field 2 to the end. 2,2 makes sure that only field 2 is used.

Solution 3:

Charlie's answer above didn't work for me on Cygwin (sort version 2.0, GNU textutils), the following did:

sort -t"," -k2 -k1 -k1