how to increment integer Columns value by 1 in SQL

Solution 1:

To add one to every value in the table...

UPDATE myTable
SET ID = ID + 1

To create a new value, one more then the previous highest (usually), use a column with IDENTITY

Solution 2:

If you want to have an unique number for each row automatically generated, this is IDENTITY as per Neil's answer.

If each time you update the table you want to increase the values (ie they are not keys):

Update MyTable
Set IDColumn = IDColumn + 1
Where <whatever>

Solution 3:

Try this:

Update Emp set testCount = ISNULL(testCount, 0) + 1 where testId=1

Solution 4:

In Oracle the code is a little bit more tricky.

You will have to create an auto-increment field with the sequence object (this object generates a number sequence).

Use the following CREATE SEQUENCE syntax:

CREATE SEQUENCE seq_person
MINVALUE 1
START WITH 1
INCREMENT BY 1
CACHE 10

The code above creates a sequence object called seq_person, that starts with 1 and will increment by 1. It will also cache up to 10 values for performance. The cache option specifies how many sequence values will be stored in memory for faster access.

To insert a new record into the "Persons" table, we will have to use the nextval function (this function retrieves the next value from seq_person sequence):

INSERT INTO Persons (ID,FirstName,LastName)
VALUES (seq_person.nextval,'Lars','Monsen')

The SQL statement above would insert a new record into the "Persons" table. The "ID" column would be assigned the next number from the seq_person sequence. The "FirstName" column would be set to "Lars" and the "LastName" column would be set to "Monsen".

Solution 5:

You can use IDENTITY which will do this for you.

CREATE TABLE [dbo].[MyTable](
    [MyTableID] [int] IDENTITY(1,1) NOT NULL,
    -- Other columns
)

When you insert your first record, you'll get an Id of 1.