Can I use a case/switch statement with two variables?
Yes you can also do:
switch (true) {
case (var1 === true && var2 === true) :
//do something
break;
case (var1 === false && var2 === false) :
//do something
break;
default:
}
This will always execute the switch, pretty much just like if/else but looks cleaner. Just continue checking your variables in the case expressions.
How about a bitwise operator? Instead of strings, you're dealing with "enums", which looks more "elegant."
// Declare slider's state "enum"
var SliderOne = {
A: 1,
B: 2,
C: 4,
D: 8,
E: 16
};
var SliderTwo = {
A: 32,
B: 64,
C: 128,
D: 256,
E: 512
};
// Set state
var s1 = SliderOne.A,
s2 = SliderTwo.B;
// Switch state
switch (s1 | s2) {
case SliderOne.A | SliderTwo.A :
case SliderOne.A | SliderTwo.C :
// Logic when State #1 is A, and State #2 is either A or C
break;
case SliderOne.B | SliderTwo.C :
// Logic when State #1 is B, and State #2 is C
break;
case SliderOne.E | SliderTwo.E :
default:
// Logic when State #1 is E, and State #2 is E or
// none of above match
break;
}
I however agree with others, 25 cases in a switch-case logic is not too pretty, and if-else might, in some cases, "look" better. Anyway.
var var1 = "something";
var var2 = "something_else";
switch(var1 + "|" + var2) {
case "something|something_else":
...
break;
case "something|...":
break;
case "...|...":
break;
}
If you have 5 possibilities for each one you will get 25 cases.
First, JavaScript's switch
is no faster than if/else
(and sometimes much slower).
Second, the only way to use switch
with multiple variables is to combine them into one primitive (string, number, etc) value:
var stateA = "foo";
var stateB = "bar";
switch (stateA + "-" + stateB) {
case "foo-bar": ...
...
}
But, personally, I would rather see a set of if
/else
statements.
Edit: When all the values are integers, it appears that switch can out-perform if/else in Chrome. See the comments.