About irrational logarithms
Solution 1:
Hint:
If $\log_b\;x$ were a rational number $\frac{p}{q}$, then
$$x^q=b^p$$
Now, go back to your initial assumption...
Edited to add: This might be of interest.
About irrational logarithms
Solution 1:
Hint:
If $\log_b\;x$ were a rational number $\frac{p}{q}$, then
$$x^q=b^p$$
Now, go back to your initial assumption...
Edited to add: This might be of interest.