How can I distinguish whether Switch,Checkbox Value is changed by user or programmatically (including by retention)?

Solution 1:

Answer 2:

A very simple answer:

Use on OnClickListener instead of OnCheckedChangeListener

    someCheckBox.setOnClickListener(new OnClickListener(){

        @Override
        public void onClick(View v) {
            // you might keep a reference to the CheckBox to avoid this class cast
            boolean checked = ((CheckBox)v).isChecked();
            setSomeBoolean(checked);
        }

    });

Now you only pick up click events and don't have to worry about programmatic changes.

Answer 1:

I have created a wrapper class (see Decorator Pattern) which handles this problem in an encapsulated way:

public class BetterCheckBox extends CheckBox {
    private CompoundButton.OnCheckedChangeListener myListener = null;
    private CheckBox myCheckBox;

    public BetterCheckBox(Context context) {
        super(context);
    }

    public BetterCheckBox(Context context, CheckBox checkBox) {
        this(context);
        this.myCheckBox = checkBox;
    }

    // assorted constructors here...    

    @Override
    public void setOnCheckedChangeListener(
        CompoundButton.OnCheckedChangeListener listener){
        if(listener != null) {
            this.myListener = listener;
        }
        myCheckBox.setOnCheckedChangeListener(listener);
    }

    public void silentlySetChecked(boolean checked){
        toggleListener(false);
        myCheckBox.setChecked(checked);
        toggleListener(true);
    }

    private void toggleListener(boolean on){
        if(on) {
            this.setOnCheckedChangeListener(myListener);
        }
        else {
            this.setOnCheckedChangeListener(null);
        }
    }
}

CheckBox can still be declared the same in XML, but use this when initializing your GUI in code:

BetterCheckBox myCheckBox;

// later...
myCheckBox = new BetterCheckBox(context,
    (CheckBox) view.findViewById(R.id.my_check_box));

If you want to set checked from code without triggering the listener, call myCheckBox.silentlySetChecked(someBoolean) instead of setChecked.

Solution 2:

Maybe You can check isShown()? If TRUE - than it's user. Works for me.

setOnCheckedChangeListener(new OnCheckedChangeListener() {
    @Override
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
        if (myCheckBox.isShown()) {// makes sure that this is shown first and user has clicked/dragged it
                  doSometing();
        }
    }
});

Solution 3:

Inside the onCheckedChanged() just check whether the user has actually checked/unchecked the radio button and then do the stuff accordingly as follows:

mMySwitch.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
 @Override
 public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
   if (buttonView.isPressed()) {
       // User has clicked check box
    }
   else
    {
       //triggered due to programmatic assignment using 'setChecked()' method.   
    }
  }
});

Solution 4:

You can remove the listener before changing it programatically and add it again, as answered in the following SO post:

https://stackoverflow.com/a/14147300/1666070

theCheck.setOnCheckedChangeListener(null);
theCheck.setChecked(false);
theCheck.setOnCheckedChangeListener(toggleButtonChangeListener);

Solution 5:

Try extending CheckBox. Something like that (not complete example):

public MyCheckBox extends CheckBox {

   private Boolean isCheckedProgramatically = false;

   public void setChecked(Boolean checked) {
       isCheckedProgramatically = true;
       super.setChecked(checked);
   }

   public Boolean isNotSetByUser() {
      return isCheckedProgramatically;
   }

}