How to count in SQL all fields with null values in one record?
Is there any way to count all fields with null values for specific record excluding PrimaryKey column?
Example:
ID Name Age City Zip
1 Alex 32 Miami NULL
2 NULL 24 NULL NULL
As output I need to get 1 and 3. Without explicitly specifying column names.
Solution 1:
declare @T table
(
ID int,
Name varchar(10),
Age int,
City varchar(10),
Zip varchar(10)
)
insert into @T values
(1, 'Alex', 32, 'Miami', NULL),
(2, NULL, 24, NULL, NULL)
;with xmlnamespaces('http://www.w3.org/2001/XMLSchema-instance' as ns)
select ID,
(
select *
from @T as T2
where T1.ID = T2.ID
for xml path('row'), elements xsinil, type
).value('count(/row/*[@ns:nil = "true"])', 'int') as NullCount
from @T as T1
Result:
ID NullCount
----------- -----------
1 1
2 3
Update:
Here is a better version. Thanks to Martin Smith.
;with xmlnamespaces('http://www.w3.org/2001/XMLSchema-instance' as ns)
select ID,
(
select T1.*
for xml path('row'), elements xsinil, type
).value('count(/row/*[@ns:nil = "true"])', 'int') as NullCount
from @T as T1
Update:
And with a bit faster XQuery expression.
;with xmlnamespaces('http://www.w3.org/2001/XMLSchema-instance' as ns)
select ID,
(
select T1.*
for xml path('row'), elements xsinil, type
).value('count(//*/@ns:nil)', 'int') as NullCount
from @T as T1
Solution 2:
SELECT id,
CASE WHEN Name IS NULL THEN 1 ELSE 0 END +
CASE WHEN City IS NULL THEN 1 ELSE 0 END +
CASE WHEN Zip IS NULL THEN 1 ELSE 0 END
FROM YourTable
If you do not want explicit column names in query, welcome to dynamic querying
DECLARE @sql NVARCHAR(MAX) = ''
SELECT @sql = @sql + N' CASE WHEN '+QUOTENAME(c.name)+N' IS NULL THEN 1 ELSE 0 END +'
FROM sys.tables t
JOIN sys.columns c
ON t.object_id = c.object_id
WHERE
c.is_nullable = 1
AND t.object_id = OBJECT_ID('YourTableName')
SET @sql = N'SELECT id, '+@sql +N'+0 AS Cnt FROM [YourTableName]'
EXEC(@sql)