Why should the assignment operator return a reference to the object?

The usual form returns a reference to the target object to allow assignment chaining. Otherwise, it wouldn't be possible to do:

Foo a, b, c;
// ...
a = b = c;

Still, keep in mind that getting right the assigment operator is tougher than it might seem.

The return type doesn't matter when you're just performing a single assignment in a statement like this:

x = y;

It starts to matter when you do this:

if ((x = y)) {

... and really matters when you do this:

x = y = z;

That's why you return the current object: to allow chaining assignments with the correct associativity. It's a good general practice.

Your assignment operator should always do these three things:

1. Take a const-reference input (const MyClass &rhs) as the right hand side of the assignment. The reason for this should be obvious, since we don't want to accidentally change that value; we only want to change what's on the left hand side.

2. Always return a reference to the newly altered left hand side, return *this. This is to allow operator chaining, e.g. a = b = c;.

3. Always check for self assignment (this == &rhs). This is especially important when your class does its own memory allocation.

   MyClass& MyClass::operator=(const MyClass &rhs) {
       // Check for self-assignment!
       if (this == &rhs) // Same object?
           return *this; // Yes, so skip assignment, and just return *this.
   
       ... // Deallocate, allocate new space, copy values, etc...
   
       return *this; //Return self
   }