Expression with last digits different
Solution 1:
HINT : $$(x+3)(x+4)-(x+5)(x+2)=3\times 4-5\times 2$$
Solution 2:
Hint $\ a\!+\!b = c\!+\!d\,\Rightarrow\, (x\!+\!a)(x\!+\!b)-(x\!+\!c)(x\!+\!d) = ab\!-\!cd,\ $ and conversely.
HINT : $$(x+3)(x+4)-(x+5)(x+2)=3\times 4-5\times 2$$
Hint $\ a\!+\!b = c\!+\!d\,\Rightarrow\, (x\!+\!a)(x\!+\!b)-(x\!+\!c)(x\!+\!d) = ab\!-\!cd,\ $ and conversely.