Count number of occurrences of a substring in a string

Solution 1:

string.count(substring), like in:

>>> "abcdabcva".count("ab")
2

Update:

As pointed up in the comments, this is the way to do it for non overlapping occurrences. If you need to count overlapping occurrences, you'd better check the answers at: "Python regex find all overlapping matches?", or just check my other answer below.

Solution 2:

s = 'arunununghhjj'
sb = 'nun'
results = 0
sub_len = len(sb)
for i in range(len(s)):
    if s[i:i+sub_len] == sb:
        results += 1
print results

Count number of occurrences of a substring in a string

Solution 1:

Update:

Solution 2:

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