Comparing Strings in Cocoa
I have tried:
- (NSString*) generateString
{
NSString* stringToReturn = @"thisString";
return stringToReturn;
}
- (void) otherMethod
{
NSString *returnedString = [self generateString];
if (returnedString == @"thisString")
{ // Do this }
else if (returnedString == @"thatString")
{ // Do that }
}
Which never matches.
I have then tried
if ([returnedString compare:@"thisString"] == 1)
But the compare method always returns 1 for me, even when comparing with a different string.
What is the correct way to do this, and what result should I expect?
Solution 1:
First of all, you are using the ==
operator to compare two object pointers (of type NSString *
). So that returns true when the pointers are the same, not when the strings have the same contents. If you wanted to compare whether two strings are the same, you should use isEqualToString:
or isEqual:
(isEqual:
is more general as it works for all types of objects).
Second, compare:
returns 0
(NSOrderSame
) when they are the same, and 1
(NSOrderedDescending
) when the first is greater than the second. So in fact it returns 1 only when they are different (specifically, when the first is greater than the second).
Solution 2:
[returnedString isEqualToString: @"thisString"]
Solution 3:
When comparing two identical strings compare
will return NSOrderedSame
, which is 0. It can also return NSOrderedAscending
, -1, and NSOrderedDescending
, 1.
You may prefer to use isEqualToString
which returns YES or NO.
Solution 4:
if ([returnedString isEqualToString:@"thisString"])
NSLog(@"Equal");
else
NSLog(@"Not Equal");
Solution 5:
The == operator when applied to objects check whether the pointers are equal.
You have to use -compare
method or one of its companions -compare:options:
-compare:options:range:
or -compare:options:range:locale:
which return a NSComparisonResult
(NSOrderAscending
, NSOrderSame
, NSOrderDescending
)
If you just need equality comparison, you can use -isEqualToString:
which returns a BOOL
value.