JSON Validator in Ubuntu 16.04

Try jsonlint:

sudo apt install jsonlint

The basic usage syntax is

jsonlint YOUR-FILE.JSON

You find its manual by typing man jsonlint or visiting its online manpage:

An excerpt:

NAME
       jsonlint - A JSON syntax validator and formatter tool

SYNOPSIS
       jsonlint [-v][-s|-S][-f|-F][-ecodec]inputfile.json...

[...]

OPTIONS
       The  return  status  will  be  0 if the file is legal JSON, or non-zero
       otherwise.  Use -v to see the warning details.

       [...]

       -v, --verbose
              Show details of lint checking
       -s, --strict
              Be strict in what is considered legal JSON (the default)
       -S, --nonstrict
              Be loose in what is considered legal JSON
       -f, --format
              Reformat the JSON (if legal) to stdout

[...]

So you can see whether your JSON is valid by checking the return code of jsonlint. You can see it by running echo $? right afterwards (0=OK, 1=invalid), or by evaluating it using &&, || or if.

I tried jsonlint but it doesn't work.

jq . may-file.json work nice!

Hope this feedback is helpful.

jq will spit out the error explicitly, and you can also check the exit status, which is 1 for parse errors, and obviously 0 for successes.

For example:

% jq '.' <<<'{"foo": "spam", "bar": 1}'
{
  "bar": 1,
  "foo": "spam"
}

% echo $?
0

Now, let's replace : with = after "bar"-- making the input an invalid json:

% jq '.' <<<'{"foo": "spam", "bar"= 1}'
parse error: Invalid numeric literal at line 1, column 23

% echo $?                                  
1

You can do this using python json.tool module

echo '{"name": "dedunu", "country": "LKA"}' | python -m json.tool

If you have a file you can use it as below.

python -m json.tool file.json

But the problem with this command is that you won't get a detail about the problem in JSON file. I found the answer from this link.