Create table with jQuery - append
This line:
$('#here_table').append( '<tr><td>' + 'result' + i + '</td></tr>' );
Appends to the div#here_table
not the new table
.
There are several approaches:
/* Note that the whole content variable is just a string */
var content = "<table>"
for(i=0; i<3; i++){
content += '<tr><td>' + 'result ' + i + '</td></tr>';
}
content += "</table>"
$('#here_table').append(content);
But, with the above approach it is less manageable to add styles and do stuff dynamically with <table>
.
But how about this one, it does what you expect nearly great:
var table = $('<table>').addClass('foo');
for(i=0; i<3; i++){
var row = $('<tr>').addClass('bar').text('result ' + i);
table.append(row);
}
$('#here_table').append(table);
Hope this would help.
You need to append the tr
inside the table
so I updated your selector inside your loop and removed the closing table
because it is not necessary.
$('#here_table').append( '<table />' );
for(i=0;i<3;i++){
$('#here_table table').append( '<tr><td>' + 'result' + i + '</td></tr>' );
}
The main problem was that you were appending the tr
to the div
here_table.
Edit: Here is a JavaScript version if performance is a concern. Using document fragment will not cause a reflow for every iteration of the loop
var doc = document;
var fragment = doc.createDocumentFragment();
for (i = 0; i < 3; i++) {
var tr = doc.createElement("tr");
var td = doc.createElement("td");
td.innerHTML = "content";
tr.appendChild(td);
//does not trigger reflow
fragment.appendChild(tr);
}
var table = doc.createElement("table");
table.appendChild(fragment);
doc.getElementById("here_table").appendChild(table);
When you use append
, jQuery expects it to be well-formed HTML (plain text counts). append
is not like doing +=
.
You need to make the table first, then append it.
var $table = $('<table/>');
for(var i=0; i<3; i++){
$table.append( '<tr><td>' + 'result' + i + '</td></tr>' );
}
$('#here_table').append($table);
Or do it this way to use ALL jQuery. The each can loop through any data be it DOM elements or an array/object.
var data = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight'];
var numCols = 1;
$.each(data, function(i) {
if(!(i%numCols)) tRow = $('<tr>');
tCell = $('<td>').html(data[i]);
$('table').append(tRow.append(tCell));
});
http://jsfiddle.net/n7cyE/93/