Error message "unreported exception java.io.IOException; must be caught or declared to be thrown"
Error:
filecontent.java:15: unreported exception java.io.IOException; must be caught or declared to be thrown
showfile(); ^ filecontent.java:78: unreported exception java.io.IOException; must be caught or declared to be thrown
showfile(); ^
I have already thrown java.io.IOException, but still it shows these errors.
My code:
import java.awt.*;
import java.awt.event.*;
import java.io.*;
class filecontent extends Frame implements ActionListener
{
TextField t[] = new TextField[4];
TextArea ta[] = new TextArea[4];
Button submit;
Panel p1;
filecontent()
{
setGUI();
setRegister();
showfile();
setTitle("FileData");
setVisible(true);
setSize(300, 300);
/* addWindowListener(new WindowAdapter()
{
public void windowClosing(WindowEvent we)
{
System.exit(0);
}
});
*/
}
void setGUI()
{
p1 = new Panel();
p1.setLayout(new GridLayout(5, 4, 10, 10));
for(int i=0; i<4; i++)
{
t[i] = new TextField(10);
ta[i] = new TextArea("");
p1.add(t[i]);
p1.add(ta[i]);
}
submit = new Button("Submit");
p1.add(submit);
}
void setRegister()
{
submit.addActionListener(this);
}
void showfile() throws java.io.IOException
{
FileReader fin[] = new FileReader[4];
FileReader fn;
// br[]=new BufferedReader[4];
for(int i=0;i<4;i++)
{
fin[i]=new FileReader(t[i].getText());
}
int cnt = 1;
String s;
fn = fin[0];
BufferedReader br = new BufferedReader(fn);
while(cnt <= 4)
{
if((s=br.readLine()) != null)
{
ta[cnt-1].append(s+"");
}
else
{
cnt++;
fn = fin[cnt-1];
ta[cnt-1].setText("");
}
}
}
public void actionPerformed(ActionEvent ae)
{
if(ae.getSource()==submit)
{
showfile();
}
}
public static void main(String ar[])
{
new filecontent();
}
}
void showfile() throws java.io.IOException <-----
Your showfile()
method throws IOException
, so whenever you use it you have to either catch that exception or again thorw it. Something like:
try {
showfile();
}
catch(IOException e) {
e.printStackTrace();
}
You should learn about exceptions in Java.
Exceptions bubble up the stack. If a caller calls a method that throws a checked exception, like IOException, it must also either catch the exception, or itself throw it.
In the case of the first block:
filecontent()
{
setGUI();
setRegister();
showfile();
setTitle("FileData");
setVisible(true);
setSize(300, 300);
/*
addWindowListener(new WindowAdapter()
{
public void windowClosing(WindowEvent we)
{
System.exit(0);
}
});
*/
}
You would have to include a try catch block:
filecontent()
{
setGUI();
setRegister();
try {
showfile();
}
catch (IOException e) {
// Do something here
}
setTitle("FileData");
setVisible(true);
setSize(300, 300);
/*
addWindowListener(new WindowAdapter()
{
public void windowClosing(WindowEvent we)
{
System.exit(0);
}
});
*/
}
In the case of the second:
public void actionPerformed(ActionEvent ae)
{
if (ae.getSource() == submit)
{
showfile();
}
}
You cannot throw IOException from this method as its signature is determined by the interface, so you must catch the exception within:
public void actionPerformed(ActionEvent ae)
{
if(ae.getSource()==submit)
{
try {
showfile();
}
catch (IOException e) {
// Do something here
}
}
}
Remember, the showFile() method is throwing the exception; that's what the "throws" keyword indicates that the method may throw that exception. If the showFile() method is throwing, then whatever code calls that method must catch, or themselves throw the exception explicitly by including the same throws IOException addition to the method signature, if it's permitted.
If the method is overriding a method signature defined in an interface or superclass that does not also declare that the method may throw that exception, you cannot declare it to throw an exception.