How do I compare a generic type to its default value? [duplicate]

To avoid boxing, the best way to compare generics for equality is with EqualityComparer<T>.Default. This respects IEquatable<T> (without boxing) as well as object.Equals, and handles all the Nullable<T> "lifted" nuances. Hence:

if(EqualityComparer<T>.Default.Equals(obj, default(T))) {
    return obj;
}

This will match:

• null for classes
• null (empty) for Nullable<T>
• zero/false/etc for other structs

How about this:

if (object.Equals(myArgument, default(T)))
{
    //...
}

Using the static object.Equals() method avoids the need for you to do the null check yourself. Explicitly qualifying the call with object. probably isn't necessary depending on your context, but I normally prefix static calls with the type name just to make the code more soluble.

I was able to locate a Microsoft Connect article that discusses this issue in some detail:

Unfortunately, this behavior is by design and there is not an easy solution to enable use of with type parameters that may contain value types.

If the types are known to be reference types, the default overload of defined on object tests variables for reference equality, although a type may specify its own custom overload. The compiler determines which overload to use based on the static type of the variable (the determination is not polymorphic). Therefore, if you change your example to constrain the generic type parameter T to a non-sealed reference type (such as Exception), the compiler can determine the specific overload to use and the following code would compile:

public class Test<T> where T : Exception

If the types are known to be value types, performs specific value equality tests based on the exact types used. There is no good "default" comparison here since reference comparisons are not meaningful on value types and the compiler cannot know which specific value comparison to emit. The compiler could emit a call to ValueType.Equals(Object) but this method uses reflection and is quite inefficient compared to the specific value comparisons. Therefore, even if you were to specify a value-type constraint on T, there is nothing reasonable for the compiler to generate here:

public class Test<T> where T : struct

In the case you presented, where the compiler does not even know whether T is a value or reference type, there is similarly nothing to generate that would be valid for all possible types. A reference comparison would not be valid for value types and some sort of value comparison would be unexpected for reference types that do not overload.

Here is what you can do...

I have validated that both of these methods work for a generic comparison of reference and value types:

object.Equals(param, default(T))

or

EqualityComparer<T>.Default.Equals(param, default(T))

To do comparisons with the "==" operator you will need to use one of these methods:

If all cases of T derive from a known base class you can let the compiler know using generic type restrictions.

public void MyMethod<T>(T myArgument) where T : MyBase

The compiler then recognizes how to perform operations on MyBase and will not throw the "Operator '==' cannot be applied to operands of type 'T' and 'T'" error that you are seeing now.

Another option would be to restrict T to any type that implements IComparable.

public void MyMethod<T>(T myArgument) where T : IComparable

And then use the CompareTo method defined by the IComparable interface.