How can I break out of two nested for loops in Objective-C?

I have two for loops nested like this:

for(...) {
    for(...) {

    }
}

I know that there is a break statement. But I am confused about if it breaks both loops or just the one in which it was called? I need to break both ones as soon as I see that it doesn't make sense to iterate more times over.

If using goto simplifies the code, then it would be appropriate.

for (;;) 
{
    for (;;) 
    {
        break; /* breaks inner loop */
    } 
    for (;;) 
    {
        goto outer; /* breaks outer loop */
    }
} 
outer:;

break breaks out of one loop, but you can add a check to the outer loop which breaks when the inner breaks.

bool dobreak = false;
for ( ..; !dobreak && ..; .. ) {
   for ( ... ) {
      if (...) {
         dobreak = true;
         break;
      }
   }
}

The break statement only gets you out of the innermost loop. If you don't want the added overhead in code, memory and performance of a dedicated state variable, I recommend refactoring the code out into a function or method of its own, and using return to get out of all the loops:

void do_lots_of_work(void)
{
  int i, j;

  for(i=0; i<10 ; i++)
  {
    for(j=0;j< 10; j++)
    {
     ..
     ..
     if(disaster_struck())
      return; /* Gets us out of the loops, and the function too. */
    }
  }
}