Super in Backbone

You'll want to use:

Backbone.Model.prototype.clone.call(this);

This will call the original clone() method from Backbone.Model with the context of this(The current model).

From Backbone docs:

Brief aside on super: JavaScript does not provide a simple way to call super — the function of the same name defined higher on the prototype chain. If you override a core function like set, or save, and you want to invoke the parent object's implementation, you'll have to explicitly call it.

var Note = Backbone.Model.extend({
 set: function(attributes, options) {
 Backbone.Model.prototype.set.apply(this, arguments);
 ...
 }    
});

You can also use the __super__ property which is a reference to the parent class prototype:

var MyModel = Backbone.Model.extend({
  clone: function(){
    MyModel.__super__.clone.call(this);
  }
});