Serialize an object to XElement and Deserialize it in memory

You can use these two extension methods to serialize and deserialize between XElement and your objects.

public static XElement ToXElement<T>(this object obj)
{
    using (var memoryStream = new MemoryStream())
    {
        using (TextWriter streamWriter = new StreamWriter(memoryStream))
        {
            var xmlSerializer = new XmlSerializer(typeof(T));
            xmlSerializer.Serialize(streamWriter, obj);
            return XElement.Parse(Encoding.ASCII.GetString(memoryStream.ToArray()));
        }
    }
}

public static T FromXElement<T>(this XElement xElement)
{
        var xmlSerializer = new XmlSerializer(typeof(T));
        return (T)xmlSerializer.Deserialize(xElement.CreateReader());
}

USAGE

XElement element = myClass.ToXElement<MyClass>();
var newMyClass = element.FromXElement<MyClass>();

You can use XMLSerialization

XML serialization is the process of converting an object's public properties and fields to a serial format (in this case, XML) for storage or transport. Deserialization re-creates the object in its original state from the XML output. You can think of serialization as a way of saving the state of an object into a stream or buffer. For example, ASP.NET uses the XmlSerializer class to encode XML Web service messages

and XDocument Represents an XML document to achieve this

   using System;
using System.Linq;
using System.Xml;
using System.Xml.Linq;
using System.Xml.Serialization;


namespace ConsoleApplication5
{
  public class Person
  {
    public int Age { get; set; }
    public string Name { get; set; }
  }

  class Program
  {
    static void Main(string[] args)
    {

      XmlSerializer xs = new XmlSerializer(typeof(Person));

      Person p = new Person();
      p.Age = 35;
      p.Name = "Arnold";

      Console.WriteLine("\n Before serializing...\n");
      Console.WriteLine(string.Format("Age = {0} Name = {1}", p.Age,p.Name));

      XDocument d = new XDocument();
      using (XmlWriter xw = d.CreateWriter())
        xs.Serialize(xw, p);

      // you can use LINQ on elm now

      XElement elm = d.Root;

      Console.WriteLine("\n From XElement...\n");

      elm.Elements().All(e => { Console.WriteLine(string.Format("element name {0} , element value {1}", e.Name, e.Value)); return true; });

      //deserialize back to object
      Person pDeserialized = xs.Deserialize((d.CreateReader())) as Person;

      Console.WriteLine("\n After deserializing...\n");
      Console.WriteLine(string.Format("Age = {0} Name = {1}", p.Age, p.Name));

      Console.ReadLine();

    }
  }


}

and here is output

(Late answer)

Serialize:

var doc = new XDocument();
var xmlSerializer = new XmlSerializer(typeof(MyClass));
using (var writer = doc.CreateWriter())
{
    xmlSerializer.Serialize(writer, obj);
}
// now you can use `doc`(XDocument) or `doc.Root` (XElement)

Deserialize:

MyClass obj; 
using(var reader = doc.CreateReader())
{
    obj = (MyClass)xmlSerializer.Deserialize(reader);
}