Cannot obtain value of local or argument as it is not available at this instruction pointer, possibly because it has been optimized away
Visual Studio 2010 kills (there is no other word) data in one of the arguments of the function in the unsafe block. What could cause this error? The following message shows by the debugger.
Cannot obtain value of local or argument as it is not available at this instruction pointer, possibly because it has been optimized away.
Go to Project Properties and under Build Make sure that the "Optimize Code" checkbox is unchecked.
Also, set the "Debug Info" dropdown to "Full" in the Advanced Options (Under Build tab).
Also In VS 2015 Community Edition
go to Debug->Options or Tools->Options
and check Debugging->General->Suppress JIT optimization on module load (Managed only)
If you compile with optimizations enabled, then many variables will be removed; for example:
SomeType value = GetValue();
DoSomething(value);
here the local variable value
would typically get removed, keeping the value on the stack instead - a bit like as if you had written:
DoSomething(GetValue());
Also, if a return value isn't used at all, then it will be dropped via "pop" (rather than stored in a local via "stloc", and again; the local will not exist).
Because of this, in such a build the debugger can't get the current value of value
because it doesn't exist - it only exists for the brief instant between GetValue()
and DoSomething(...)
.
So; if you want to debug... don't use a release build! or at least, disable optimizations while you debug.
In visual Studio 2017 goto Debug->Option then check Debugging->general-> and check this option