What Regex would capture everything from ' mark to the end of a line?

'.*

I believe you need the option, Multiline.

The appropriate regex would be the ' char followed by any number of any chars [including zero chars] ending with an end of string/line token:

'.*$

And if you wanted to capture everything after the ' char but not include it in the output, you would use:

(?<=').*$

This basically says give me all characters that follow the ' char until the end of the line.

Edit: It has been noted that $ is implicit when using .* and therefore not strictly required, therefore the pattern:

'.* 

is technically correct, however it is clearer to be specific and avoid confusion for later code maintenance, hence my use of the $. It is my belief that it is always better to declare explicit behaviour than rely on implicit behaviour in situations where clarity could be questioned.

'.*$

Starting with a single quote ('), match any character (.) zero or more times (*) until the end of the line ($).

When I tried '.* in windows (Notepad ++) it would match everything after first ' until end of last line.

To capture everything until end of that line I typed the following:

'.*?\n

This would only capture everything from ' until end of that line.