mongodb/mongoose findMany - find all documents with IDs listed in array

I have an array of _ids and I want to get all docs accordingly, what's the best way to do it ?

Something like ...

// doesn't work ... of course ...

model.find({
    '_id' : [
        '4ed3ede8844f0f351100000c',
        '4ed3f117a844e0471100000d', 
        '4ed3f18132f50c491100000e'
    ]
}, function(err, docs){
    console.log(docs);
});

The array might contain hundreds of _ids.

Solution 1:

The find function in mongoose is a full query to mongoDB. This means you can use the handy mongoDB $in clause, which works just like the SQL version of the same.

model.find({
    '_id': { $in: [
        mongoose.Types.ObjectId('4ed3ede8844f0f351100000c'),
        mongoose.Types.ObjectId('4ed3f117a844e0471100000d'), 
        mongoose.Types.ObjectId('4ed3f18132f50c491100000e')
    ]}
}, function(err, docs){
     console.log(docs);
});

This method will work well even for arrays containing tens of thousands of ids. (See Efficiently determine the owner of a record)

I would recommend that anybody working with mongoDB read through the Advanced Queries section of the excellent Official mongoDB Docs

Solution 2:

Ids is the array of object ids:

const ids =  [
    '4ed3ede8844f0f351100000c',
    '4ed3f117a844e0471100000d', 
    '4ed3f18132f50c491100000e',
];

Using Mongoose with callback:

Model.find().where('_id').in(ids).exec((err, records) => {});

Using Mongoose with async function:

const records = await Model.find().where('_id').in(ids).exec();

Or more concise:

const records = await Model.find({ '_id': { $in: ids } });

Don't forget to change Model with your actual model.

Solution 3:

Combining Daniel's and snnsnn's answers:

let ids = ['id1','id2','id3']
let data = await MyModel.find(
  {'_id': { $in: ids}}
);

Simple and clean code. It works and tested against:

"mongodb": "^3.6.0", "mongoose": "^5.10.0",