Rx: How can I respond immediately, and throttle subsequent requests

Solution 1:

Here's my approach. It's similar to others that have gone before, but it doesn't suffer the over-zealous window production problem.

The desired function works a lot like Observable.Throttle but emits qualifying events as soon as they arrive rather than delaying for the duration of the throttle or sample period. For a given duration after a qualifying event, subsequent events are suppressed.

Given as a testable extension method:

public static class ObservableExtensions
{
    public static IObservable<T> SampleFirst<T>(
        this IObservable<T> source,
        TimeSpan sampleDuration,
        IScheduler scheduler = null)
    {
        scheduler = scheduler ?? Scheduler.Default;
        return source.Publish(ps => 
            ps.Window(() => ps.Delay(sampleDuration,scheduler))
              .SelectMany(x => x.Take(1)));
    }
}

The idea is to use the overload of Window that creates non-overlapping windows using a windowClosingSelector that uses the source time-shifted back by the sampleDuration. Each window will therefore: (a) be closed by the first element in it and (b) remain open until a new element is permitted. We then simply select the first element from each window.

Rx 1.x Version

The Publish extension method used above is not available in Rx 1.x. Here is an alternative:

public static class ObservableExtensions
{
    public static IObservable<T> SampleFirst<T>(
        this IObservable<T> source,
        TimeSpan sampleDuration,
        IScheduler scheduler = null)
    {
        scheduler = scheduler ?? Scheduler.Default;
        var sourcePub = source.Publish().RefCount();
        return sourcePub.Window(() => sourcePub.Delay(sampleDuration,scheduler))
                        .SelectMany(x => x.Take(1));
    }
}

Solution 2:

The solution I found after a lot of trial and error was to replace the throttled subscription with the following:

subject
    .Window(() => { return Observable.Interval(timeout); })
    .SelectMany(x => x.Take(1))
    .Subscribe(i => DoStuff(i));

Edited to incorporate Paul's clean-up.