When to use const char * and when to use const char []

I know they are different, I know how they are different and I read all questions I could find regarding char* vs char[]

But all those answers never tell when they should be used.

So my question is:

When do you use

const char *text = "text";

and when do you use

const char text[] = "text";

Is there any guideline or rule?

As an example, which one is better:

void withPointer()
{
    const char *sz = "hello";
    std::cout << sz << std::endl;
}

void withArray()
{
    const char sz[] = "hello";
    std::cout << sz << std::endl;
}

(I know std::string is also an option but I specifically want to know about char pointer/array)

Both are distinctly different, For a start:

1. The First creates a pointer.
2. The second creates an array.

Read on for more detailed explanation:

The Array version:

char text[] = "text"; 

Creates an array that is large enough to hold the string literal "text", including its NULL terminator. The array text is initialized with the string literal "text".The array can be modified at a later time. Also, the array's size is known even at compile time, so sizeof operator can be used to determine its size.

The pointer version:

char *text  = "text"; 

Creates a pointer to point to a string literal "text". This is faster than the array version, but string pointed by the pointer should not be changed, because it is located in an read only implementation defined memory. Modifying such an string literal results in Undefined Behavior.

In fact C++03 deprecates use of string literal without the const keyword. So the declaration should be:

const char*text = "text";

Also,you need to use the strlen() function, and not sizeof to find size of the string since the sizeof operator will just give you the size of the pointer variable.

Which version is better?

Depends on the Usage.

• If you do not need to make any changes to the string, use the pointer version.
• If you intend to change the data, use the array version.

EDIT: It was just brought to my notice(in comments) that the OP seeks difference between:

const char text[] and const char* text

Well the above differing points still apply except the one regarding modifying the string literal. With the const qualifier the array test is now an array containing elements of the type const char which implies they cannot be modified.

Given that, I would choose the array version over the pointer version because the pointer can be(by mistake)easily reseated to another pointer and the string could be modified through that another pointer resulting in an UB.

Probably the biggest difference is that you cannot use the sizeof operator with the pointer to get the size of the buffer begin pointed to, where-as with the const char[] version you can use sizeof on the array variable to get the memory footprint size of the array in bytes. So it really depends on what you're wanting to-do with the pointer or buffer, and how you want to use it.

For instance, doing:

void withPointer()
{
    const char *sz = "hello";
    std::cout << sizeof(sz) << std::endl;
}

void withArray()
{
    const char sz[] = "hello";
    std::cout << sizeof(sz) << std::endl;
}

will give you very different answers.

In general to answer these types of questions, use the one that's most explicit.

In this case, const char[] wins because it contains more detailed information about the data within -- namely, the size of the buffer.