Get size of all tables in database
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
If you are using SQL Server Management Studio (SSMS), instead of running a query (which in my case returned duplicate rows) you can run a standard report.
- Right click on the database
- Navigate to Reports > Standard Reports > Disk Usage By Table
Note: The database compatibility level must be set to 90 or above for this to work correctly. See http://msdn.microsoft.com/en-gb/library/bb510680.aspx
sp_spaceused can get you information on the disk space used by a table, indexed view, or the whole database.
For example:
USE MyDatabase; GO
EXEC sp_spaceused N'User.ContactInfo'; GO
This reports the disk usage information for the ContactInfo table.
To use this for all tables at once:
USE MyDatabase; GO
sp_msforeachtable 'EXEC sp_spaceused [?]' GO
You can also get disk usage from within the right-click Standard Reports functionality of SQL Server. To get to this report, navigate from the server object in Object Explorer, move down to the Databases object, and then right-click any database. From the menu that appears, select Reports, then Standard Reports, and then "Disk Usage by Partition: [DatabaseName]".