Derivative of Integral with variable bounds
Solution 1:
Yes is correct, remember that $$\frac{d}{dx}\int_{g(x)}^{f(x)}h(t)\,dt=h(f(x))\cdot f'(x)-h(g(x))\cdot g'(x) $$
this is by the second theorem of calculus and by chain rule.
Derivative of Integral with variable bounds
Solution 1:
Yes is correct, remember that $$\frac{d}{dx}\int_{g(x)}^{f(x)}h(t)\,dt=h(f(x))\cdot f'(x)-h(g(x))\cdot g'(x) $$
this is by the second theorem of calculus and by chain rule.