extract the date part from DateTime in C# [duplicate]
Solution 1:
DateTime
is a DataType which is used to store both Date
and Time
. But it provides Properties to get the Date
Part.
You can get the Date part from Date
Property.
http://msdn.microsoft.com/en-us/library/system.datetime.date.aspx
DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
Console.WriteLine(date1.ToString());
// Get date-only portion of date, without its time.
DateTime dateOnly = date1.Date;
// Display date using short date string.
Console.WriteLine(dateOnly.ToString("d"));
// Display date using 24-hour clock.
Console.WriteLine(dateOnly.ToString("g"));
Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));
// The example displays the following output to the console:
// 6/1/2008 7:47:00 AM
// 6/1/2008
// 6/1/2008 12:00 AM
// 06/01/2008 00:00
Solution 2:
There is no way to "discard" the time component.
DateTime.Today
is the same as:
DateTime d = DateTime.Now.Date;
If you only want to display only the date portion, simply do that - use ToString
with the format string you need.
For example, using the standard format string "D" (long date format specifier):
d.ToString("D");
Solution 3:
When comparing only the date of the datatimes, use the Date property. So this should work fine for you
datetime1.Date == datetime2.Date
Solution 4:
DateTime d = DateTime.Today.Date;
Console.WriteLine(d.ToShortDateString()); // outputs just date
if you want to compare dates, ignoring the time part, make an use of DateTime.Year
and DateTime.DayOfYear
properties.
code snippet
DateTime d1 = DateTime.Today;
DateTime d2 = DateTime.Today.AddDays(3);
if (d1.Year < d2.Year)
Console.WriteLine("d1 < d2");
else
if (d1.DayOfYear < d2.DayOfYear)
Console.WriteLine("d1 < d2");