How to use "Share image using" sharing Intent to share images in android?

I have image galley app in that app I placed all the images into the drawable-hdpi folder. and i called images in my activity like this :

private Integer[] imageIDs = {
        R.drawable.wall1, R.drawable.wall2,
        R.drawable.wall3, R.drawable.wall4,
        R.drawable.wall5, R.drawable.wall6,
        R.drawable.wall7, R.drawable.wall8,
        R.drawable.wall9, R.drawable.wall10
};

So now i want know how do i share this images using sharing Intent i putted sharing code like this :

     Button shareButton = (Button) findViewById(R.id.share_button);
     shareButton.setOnClickListener(new View.OnClickListener() {
     public void onClick(View v) {
       
        Intent sharingIntent = new Intent(Intent.ACTION_SEND);
        Uri screenshotUri = Uri.parse(Images.Media.EXTERNAL_CONTENT_URI + "/" + imageIDs);

        sharingIntent.setType("image/jpeg");
        sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
        startActivity(Intent.createChooser(sharingIntent, "Share image using"));  
    
         }
    });

And i have sharing button also when i click on share button Sharing box is opening But when i cliked any service mostly its crashing or some services say : unable to open image So how i can fix this or is there any othere format code to share images ????

Edit :

I tried using the code below. But its not working.

Button shareButton = (Button) findViewById(R.id.share_button);
     shareButton.setOnClickListener(new View.OnClickListener() {
     public void onClick(View v) {

        Intent sharingIntent = new Intent(Intent.ACTION_SEND);
        Uri screenshotUri = Uri.parse("android.resource://com.android.test/*");
        try {
            InputStream stream = getContentResolver().openInputStream(screenshotUri);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        sharingIntent.setType("image/jpeg");
        sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
        startActivity(Intent.createChooser(sharingIntent, "Share image using"));  

         }
    });

If don't mind somebody plz correct my above code OR give me a proper example plz How do i Share my images from drawable-hdpi folder

Solution 1:

Bitmap icon = mBitmap;
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
icon.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
File f = new File(Environment.getExternalStorageDirectory() + File.separator + "temporary_file.jpg");
try {
    f.createNewFile();
    FileOutputStream fo = new FileOutputStream(f);
    fo.write(bytes.toByteArray());
} catch (IOException e) {                       
        e.printStackTrace();
}
share.putExtra(Intent.EXTRA_STREAM, Uri.parse("file:///sdcard/temporary_file.jpg"));
startActivity(Intent.createChooser(share, "Share Image"));

Solution 2:

The solution proposed from superM worked for me for a long time, but lately I tested it on 4.2 (HTC One) and it stopped working there. I am aware that this is a workaround, but it was the only one which worked for me with all devices and versions.

According to the documentation, developers are asked to "use the system MediaStore" to send binary content. This, however, has the (dis-)advantage, that the media content will be saved permanently on the device.

If this is an option for you, you might want to grant permission WRITE_EXTERNAL_STORAGE and use the system-wide MediaStore.

Bitmap icon = mBitmap;
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");

ContentValues values = new ContentValues();
values.put(Images.Media.TITLE, "title");
values.put(Images.Media.MIME_TYPE, "image/jpeg");
Uri uri = getContentResolver().insert(Media.EXTERNAL_CONTENT_URI,
        values);


OutputStream outstream;
try {
    outstream = getContentResolver().openOutputStream(uri);
    icon.compress(Bitmap.CompressFormat.JPEG, 100, outstream);
    outstream.close();
} catch (Exception e) {
    System.err.println(e.toString());
}

share.putExtra(Intent.EXTRA_STREAM, uri);
startActivity(Intent.createChooser(share, "Share Image"));

Solution 3:

First add permission

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>

using Bitmap from resources

Bitmap b =BitmapFactory.decodeResource(getResources(),R.drawable.userimage);
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
b.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
String path = MediaStore.Images.Media.insertImage(getContentResolver(), b, "Title", null);
Uri imageUri =  Uri.parse(path);
share.putExtra(Intent.EXTRA_STREAM, imageUri);
startActivity(Intent.createChooser(share, "Select"));

Tested via bluetooth and other messengers

Solution 4:

I found the easiest way to do this is by using the MediaStore to temporarily store the image that you want to share:

Drawable mDrawable = mImageView.getDrawable();
Bitmap mBitmap = ((BitmapDrawable) mDrawable).getBitmap();

String path = MediaStore.Images.Media.insertImage(getContentResolver(), mBitmap, "Image Description", null);
Uri uri = Uri.parse(path);

Intent intent = new Intent(Intent.ACTION_SEND);
intent.setType("image/jpeg");
intent.putExtra(Intent.EXTRA_STREAM, uri);
startActivity(Intent.createChooser(intent, "Share Image"));

From: Sharing Content With Intents

Solution 5:

Simple and Easiest code you can use it to share image from gallery.

 String image_path;
            File file = new File(image_path);
            Uri uri = Uri.fromFile(file);
            Intent intent = new Intent(Intent.ACTION_SEND);
            intent .setType("image/*");
            intent .putExtra(Intent.EXTRA_STREAM, uri);
            context.startActivity(intent );