How to display list items on console window in C#
Actually you can do it pretty simple, since the list have a ForEach
method and since you can pass in Console.WriteLine
as a method group. The compiler will then use an implicit conversion to convert the method group to, in this case, an Action<int>
and pick the most specific method from the group, in this case Console.WriteLine(int)
:
var list = new List<int>(Enumerable.Range(0, 50));
list.ForEach(Console.WriteLine);
Works with strings too =)
To be utterly pedantic (and I'm not suggesting a change to your answer - just commenting for the sake of interest) Console.WriteLine
is a method group. The compiler then uses an implicit conversion from the method group to Action<int>
, picking the most specific method (Console.WriteLine(int)
in this case).
While the answers with List<T>.ForEach
are very good.
I found String.Join<T>(string separator, IEnumerable<T> values)
method more useful.
Example :
List<string> numbersStrLst = new List<string>
{ "One", "Two", "Three","Four","Five"};
Console.WriteLine(String.Join(", ", numbersStrLst));//Output:"One, Two, Three, Four, Five"
int[] numbersIntAry = new int[] {1, 2, 3, 4, 5};
Console.WriteLine(String.Join("; ", numbersIntAry));//Output:"1; 2; 3; 4; 5"
Remarks :
If separator is null, an empty string (String.Empty
) is used instead. If any member of values is null, an empty string is used instead.
Join(String, IEnumerable<String>)
is a convenience method that lets you concatenate each element in an IEnumerable(Of String) collection without first converting the elements to a string array. It is particularly useful with Language-Integrated Query (LINQ) query expressions.
This should work just fine for the problem, whereas for others, having array values. Use other overloads of this same method, String.Join Method (String, Object[])
Reference: https://msdn.microsoft.com/en-us/library/dd783876(v=vs.110).aspx
Assuming the items override ToString
appropriately:
public void WriteToConsole(IEnumerable items)
{
foreach (object o in items)
{
Console.WriteLine(o);
}
}
(There'd be no advantage in using generics in this loop - we'd end up calling Console.WriteLine(object)
anyway, so it would still box just as it does in the foreach
part in this case.)
EDIT: The answers using List<T>.ForEach
are very good.
My loop above is more flexible in the case where you have an arbitrary sequence (e.g. as the result of a LINQ expression), but if you definitely have a List<T>
I'd say that List<T>.ForEach
is a better option.
One advantage of List<T>.ForEach
is that if you have a concrete list type, it will use the most appropriate overload. For example:
List<int> integers = new List<int> { 1, 2, 3 };
List<string> strings = new List<string> { "a", "b", "c" };
integers.ForEach(Console.WriteLine);
strings.ForEach(Console.WriteLine);
When writing out the integers, this will use Console.WriteLine(int)
, whereas when writing out the strings it will use Console.WriteLine(string)
. If no specific overload is available (or if you're just using a generic List<T>
and the compiler doesn't know what T
is) it will use Console.WriteLine(object)
.
Note the use of Console.WriteLine
as a method group, by the way. This is more concise than using a lambda expression, and actually slightly more efficient (as the delegate will just be a call to Console.WriteLine
, rather than a call to a method which in turn just calls Console.WriteLine
).
You can also use List's inbuilt foreach, such as:
List<T>.ForEach(item => Console.Write(item));
This code also runs significantly faster!
The above code also makes you able to manipulate Console.WriteLine, such as doing:
List<T>.ForEach(item => Console.Write(item + ",")); //Put a,b etc.
Console.WriteLine(string.Join<TYPE>("\n", someObjectList));